One redo our could be a body of water like a dam as such, and another is something like a retention pond, taking in water
The range of temperatures in which an insect is able to live and reproduce is one element of that organism's niche, a description of its ecological requirements.
Test One: All short fur
Phenotype ratio: 4:0
Test Two: three short fur and one long fur
Phenotype ratio: 3:1
Test Three: all long fur
Phenotype ratio: 4:0
Genotypes for fur length dominant
G: FF, and Ff (These are the genotypes for short fur, short fur is a dominant gene.
P: Short fur is dominant
Genotypes and phenotypes for fur length recessive
G: ff
P: Long fur is recessive
If you have a hamster with short fur, the possible genotypes the hamster could have is FF, and Ff
If you have a hamster with long fur, the possible genotype is ff.
Answer:
It was discovered that the organisms in each of the five kingdoms have a different method of obtaining nutrients and are therefore fundamentally different.
Explanation:
New kingdoms were needed that reflected our growing knowledge of the differences between living organisms.
Answer:The ratio of the concentrations of 
and 
when the buffer has a pH of 7.02 is 0.69
Explanation:
The dissociation constant for formic acid = 
Concentration of HA= 0.5 mM
Concentration of = 0.1 mM
pH = 6.16
First we have to calculate the value of 
.
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[A^-}{[HA]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BA%5E-%7D%7B%5BHA%5D%7D)
Now put all the given values in this expression, we get:
![6.16=pK_a+\log (\frac{[0.1]}{0.5})](https://tex.z-dn.net/?f=6.16%3DpK_a%2B%5Clog%20%28%5Cfrac%7B%5B0.1%5D%7D%7B0.5%7D%29)
To calculate the ratio of the concentrations of and when the buffer has a pH of 7.02.
Using Henderson Hesselbach equation :
![7.02=6.86+\log \frac{[A^-]}{[HA]}](https://tex.z-dn.net/?f=7.02%3D6.86%2B%5Clog%20%5Cfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
![\frac{[A^-]}{[HA]}=1.44](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D%3D1.44)
![\frac{[HA]}{[A^-]}=0.69](https://tex.z-dn.net/?f=%5Cfrac%7B%5BHA%5D%7D%7B%5BA%5E-%5D%7D%3D0.69)
Thus the ratio of the concentrations of and when the buffer has a pH of 7.02 is 0.69
