Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Answer:
15/4 +6y
Step-by-step explanation:
See Image below:)
3.75 miles because 3/4 is .75 in money and the 3 is howm many miles
Answer:
a
Step-by-step explanation:
I think maybe the second one I’m not fully sure but I hope this might help
