Complete the sentences to describe the difference between static and dynamic equilibrium.
2 answers:
<span>a) An object in equilibrium has a net force of zero.
- An object is said to be in equilibrium if all the forces acting on the object are balanced, so that the net force (=resultant of the forces) acting on the object is zero.
b) Static equilibrium describes an object at rest having equal and balanced forces acting upon it.
- An object is said to be in static equilibrium if it is at rest and all the forces acting on the object are balanced, so that the net force (=resultant of the forces) acting on the object is zero. In this case, the object will remain at rest, according to Newton's second law:
</span>
<span>where the first term is the resultant of the forces acting on the object, m is its mass and a its acceleration. Since the resultant of the forces is zero, the acceleration is zero as well, and the object will remain at rest.
c) Dynamic equilibrium describes an object in motion having equal and balanced forces acting upon it.
- </span>An object is said to be in dynamic equilibrium if it is in motion and all the forces acting on the object are balanced, so that the net force (=resultant of the forces) acting on the object is zero. In this case, the object will remain in motion with constant velocity, according to Newton's second law:
where the first term is the resultant of the forces acting on the object, m is its mass and a its acceleration. Since the resultant of the forces is zero, the acceleration is zero as well, and the object will not change its velocity.
- An object is said to be in equilibrium if all the forces acting on the object are balanced, so that the net force (=resultant of the forces) acting on the object is zero.
b) Static equilibrium describes an object at rest having equal and balanced forces acting upon it.
- An object is said to be in static equilibrium if it is at rest and all the forces acting on the object are balanced, so that the net force (=resultant of the forces) acting on the object is zero. In this case, the object will remain at rest, according to Newton's second law:
</span>
<span>where the first term is the resultant of the forces acting on the object, m is its mass and a its acceleration. Since the resultant of the forces is zero, the acceleration is zero as well, and the object will remain at rest.
c) Dynamic equilibrium describes an object in motion having equal and balanced forces acting upon it.
- </span>An object is said to be in dynamic equilibrium if it is in motion and all the forces acting on the object are balanced, so that the net force (=resultant of the forces) acting on the object is zero. In this case, the object will remain in motion with constant velocity, according to Newton's second law:
where the first term is the resultant of the forces acting on the object, m is its mass and a its acceleration. Since the resultant of the forces is zero, the acceleration is zero as well, and the object will not change its velocity.
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Answer:
The new water temperature is 26.4 °C
Explanation:
Given;
mass of copper, = 26 g = 0.026 kg
temperature of copper, t = 300 °C
volume of water, V = 120 mL = 0.12 L
temperature of water, t = 21 °C
density of water, ρ = 1 kg/L
mass of water = density x volume
mass of water = (1 kg/L) x 0.12 L = 0.12 kg
heat lost by copper = heat gained by water
Both copper and water reach final temperature, T
Heat gained by water, =
cΔθ =
Heat lost by copper is given by;
504(T- 21) = 10.01(300 - T)
504 T - 10584 = 3003 - 10.01 T
504 T + 10.01 T= 3003 + 10584
514.01 T = 13587
T = (13587) / 514.01
T = 26.4 °C
Therefore, the new water temperature is 26.4 °C
Answer:
is the drop in the water temperature.
Explanation:
Given:
- mass of ice,
- mass of water,
Assuming the initial temperature of the ice to be 0° C.
<u>Apply the conservation of energy:</u>
- Heat absorbed by the ice for melting is equal to the heat lost from water to melt ice.
<u>Now from the heat equation:</u>
......................(1)
where:
latent heat of fusion of ice
specific heat of water
change in temperature
Putting values in eq. (1):
is the drop in the water temperature.