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3 years ago

If your mass is 100 kg on earth, what do you weigh on the moon?

Physics

2 answers:

galben [10]3 years ago

8 0

You’d weight about 162 N

sleet_krkn [62]3 years ago

8 0

A.) 162 N if your mass is 100 kg on earth

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Write a sentence on how these words are used in real life situations

ipn [44]

Answer:

Explanation:

You can approach an expression for the instantaneous velocity at any point on the path by taking the limit as the time interval gets smaller and smaller. Such a limiting process is called a derivative and the instantaneous velocity can be defined as.#3

For the special case of straight line motion in the x direction, the average velocity takes the form: If the beginning and ending velocities for this motion are known, and the acceleration is constant, the average velocity can also be expressed as For this special case, these expressions give the same result. Example for non-constant acceleration#1

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3 years ago

A car initially traveling at 24 m/s slams on the brakes and moves forward 196 m before coming to a complete halt. What was the m

Marrrta [24]

Answer:

$-1.47 m/s^2$

Explanation:

We can use the following SUVAT equation to solve the problem:

$v^2 - u^2 = 2ad$

where

v = 0 is the final velocity of the car

u = 24 m/s is the initial velocity

a is the acceleration

d = 196 m is the displacement of the car before coming to a stop

Solving the equation for a, we find the acceleration:

$a=\frac{v^2-u^2}{2d}=\frac{0-(24)^2}{2(196)}=-1.47 m/s^2$

4 0

3 years ago

Typically, atoms gain or lose electrons to achieve

nasty-shy [4]

Answer:

Typically, atoms gain or lose electrons to achieve a stable electron configuration.

Explanation:

3 0

3 years ago

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Momentum data about the same objects in the same closed system is shown below.

nalin [4]

Answer:

the value of x is 3.7 because they are arranged in a particular manner.

6 0

3 years ago

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Jerome plays middle linebacker for souths varsity football team. In a game against cross-town rival north, he delivered a hit to

Makovka662 [10]

The momentum change of the running back is - 664.2 kg m/s or 664 west.

<u>Explanation:</u>

Momentum is defined as the change in velocity of any object along with its mass. So mathematically, momentum can be derived using the product of mass with the change in velocity.

$\text { Momentum change }=m \times \Delta v$

As here mass is given as 82 kg and the initial velocity was 5.6 m/s and final velocity is 2.5 m/s.

Initial Momentum = $m \times \text { initial velocity }=82 \times 5.6=459.2 \mathrm{kg} \mathrm{m} / \mathrm{s}$

Final Momentum = $m \times \text { final velocity }=82 \times(-2.5)=-205 \mathrm{kg} \mathrm{m} / \mathrm{s}$

Momentum change = Final Momentum - Initial Momentum

Momentum change = - 205 - 459.2 = - 664.2 kg m/s or 664 west

Thus, the changing momentum is -664.2 kg m/s. The negative sign indicates that the momentum is acting in the opposite direction on changing in the direction of velocity.

7 0

3 years ago