Answer:
velocity = 62.89 m/s in 58 degree measured from the x-axis
Explanation:
Relevant information:
Before the collision, asteroid A of mass 1,000 kg moved at 100 m/s, and asteroid B of mass 2,000 kg moved at 80 m/s.
Two asteroids moving with velocities collide at right angles and stick together. Asteroid A initially moving to right direction and asteroid B initially move in the upward direction.
Before collision Momentum of A = 1000 x 100 =
kg - m/s in the right direction.
Before collision Momentum of B = 2000 x 80 = 1.6 x
kg - m/s in upward direction.
Mass of System of after collision = 1000 + 2000 = 3000 kg
Now applying the Momentum Conservation, we get
Initial momentum in right direction = final momentum in right direction =
And, Initial momentum in upward direction = Final momentum in upward direction = 1.6 x
So,
=
m/s
and
m/s
Therefore, velocity is = 
= 
= 62.89 m/s
And direction is
tan θ =
= 1.6
therefore, 
=
from x-axis
Answer:
9.4
Explanation:
magnitude is the sum of the squares.

If you are given horizontal and vertical components, treat those as the rise and run of a triangle, the rise of 8 with a run of 5 and you want to find the hypotenuse.
How do you find the long side of a triangle?
Apparently, the question is looking for A. electric potential energy;
but I don't think that's quite right. Electric potential difference is expressed in Joules / Coulomb which is the work to move a charge between 2 points
Example: If the electric field between, say, between 2 capacitor plates is
E = 100 Newtons / Coulomb then the work done in moving a unit of charge from the negative plate to the positive plate separted by 1 cm is
V = E * d = 100 Newtons / Coulomb * .01 meters = 1 Newton-meter / Coulomb
= 1 Joule / Coulomb which is the electric potential or potential difference
(The definition of electric potential between points is "the work moving a unit positive test charge from one point to the other")
Now in our above example where V = 1 Joule / Coulomb
if we move 10 Coulombs from the negative plate to the positive plate
W = V Q = 1 Joule / Coulomb * 10 Coulombs = 10 Joules
where work done has the correct units of Joules.
Your textbook should help clarify this.
Answer:
75.2° C
Explanation:
Given:
mass of the coffee, M = 500
mass of the cup, m = 240
since the coffee is mostly water ,
specific heat of the coffee, C = 4.184 J/kg.°C
specific heat of the aluminium, C' = 0.902 J/kg.°C
The heat lost by the coffee will be transferred to the aluminium cup. The process of heat transfer will continue till the temperature of the coffee and the cup will be in equilibrium (or same)
i.e
Heat lost by the coffee = heat gained by the cup
or
MC(85 - T) = mC'(T - (-20))
where, T is the temperature at the equilibrium or the final temperature
on substituting the values, we get
500 × 4.184 × (85 - T) = 240 × 0.902 × (T - (-20))
or
T = 75.2° C
Hence, the final temperature of the coffee will be 75.2° C