Check the picture below, it hits the ground when y = 0.

$\bf ~~~~~~\textit{initial velocity}\\\\
\begin{array}{llll}
~~~~~~\textit{in feet}\\\\
h(t) = -16t^2+v_ot+h_o \\\\
\end{array} 
\quad 
\begin{cases}
v_o=\stackrel{0}{\textit{initial velocity of the object}}\\\\
h_o=\stackrel{162}{\textit{initial height of the object}}\\\\
h=\stackrel{}{\textit{height of the object at "t" seconds}}
\end{cases}
\\\\\\
h(t)=-16t^2+0t+162\implies 0=-16t^2+162\implies 16t^2=162
\\\\\\
t=\cfrac{162}{16}\implies t=\cfrac{81}{8}\implies t=10\frac{1}{8}$

6 0

3 years ago

A cyclist rides into the country at an average speed of 10 miles per hour. When his bicycle gets a flat tire, he walks it back a

vladimir1956 [14]

Answer

Find out the how far into the country does he go.

To proof

Let us assume that the total diatance travelled into the country be x .

Formula

$Time =\frac{Distance}{Speed}$

As given

A cyclist rides into the country at an average speed of 10 miles per hour. When his bicycle gets a flat tire,

he walks it back at an average speed of 3 miles per hour.

If he returns home 6 and a half hours after he starts i.e the total time including the bike time and walk time of the cyclist be 6.5 hours.

Than the equation becomes

$\frac{x}{10} +\frac{x}{3} = 6.5$

L.C.M of (10,3) = 30

Than the equation becomes

3x +10x = 195

solving

13x = 195

$x = \frac{195}{13}$

x = 15 miles into the country

Hence proved

6 0

3 years ago

Please help giving brainiest

tia_tia [17]

Answer:

(0, -1); maximum

3 0

3 years ago