Option A
The solution is 
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
3x + 6y = 1 ------ eqn 1
x - 4y = 1 ------ eqn 2
We have to find solution to system of equations
We can use substitution method
From eqn 2,
x = 1 + 4y -------- eqn 3
Substitute eqn 3 in eqn 1
3(1 + 4y) + 6y = 1
3 + 12y + 6y = 1
18y = 1 - 3
18y = -2
Divide both sides by 18
Substitute the above value of y in eqn 3
Thus solution is
Answer:
m = 8 Please brainliest!
Step-by-step explanation:
Simplifying
7m + -6m = 8
Combine like terms: 7m + -6m = 1m
1m = 8
Solving
1m = 8
Solving for variable 'm'.
Move all terms containing m to the left, all other terms to the right.
Divide each side by '1'.
m = 8
Simplifying
m = 8
Answer:
8i + 4
Step-by-step explanation:
Add/subtract like terms:
7 - 3
= 4
-4i - (-12i)
-4i + 12i
= 8i
Add these together:
8i + 4
So, the simplified expression is 8i + 4
Answer:
Step-by-step explanation:
A for sure
