Last week, Clay had a beginning balance of $60 in his account. He wrote 4
1 answer:
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Answer:
1.9cm
Step-by-step explanation:
The density d of a material is related to its mass m and volume V as follows;
d = ------------------(i)
The material in question here is the lead ball.
Now, from known experiment;
the density of lead is <em>11.34g/cm³</em>
From the question, the weight/mass of the lead ball is <em>326g</em>
Substitute these values into equation (i) as follows;
11.34 =
V =
V = 28.75cm³
Now, since the ball is of course spherical, we can get the radius by using the following relation from the volume of a sphere;
V = [V = volume, r = radius]
V = 28.75cm³
=> 28.75 =
=> 3 x 28.75 = 4 π r³
=> 86.25 = 4 π r³
=> 21.5625 = π r³ [Take π = 3.142]
=> 21.5625 = (3.142) r³ [divide both sides by 3.142]
=> 6.86 = r³ [Take the cube root of both sides]
=> ∛6.86 = ∛r³
=> 1.90 = r
Therefore, the radius is 1.9cm to the nearest tenth
<em>Complete Question:</em>
<em>A twelve-sided die with sides labeled 1 through 12 will be rolled once. Each number is equally likely to be rolled, what is the probability of rolling a number greater than 10?</em>
Answer:
Step-by-step explanation:
Given
Number of Sides = 12
Required
Probability of obtaining a side greater than 10
We start by listing out the sample space;
Next, we list out digits greater than 10; Represent this with T
Probability of T is calculated as follows;
Divide the numerator and denominator by 2
<em>Hence, the required probability is </em><em />