Answer ?? It’s multiplicity

Mathematics

1 answer:

EleoNora [17]2 years ago

3 0

I think A is the answer

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The diameter of a small gear is 16 cm this is 2.5 more than 1/4 of the diameter of a larger gear ehat is the diameter of the lar

musickatia [10]

Let's say the diameter of the larger gear is "x".

the small one has a diameter of 16cm, we know that, this is 2.5 more than (1/4)x.

$\bf 16=\cfrac{1}{4}x+2.5\implies 16-2.5=\cfrac{x}{4}\implies 13.5=\cfrac{x}{4}\implies 4(13.5)=x
\\\\\\
54=x$

6 0

2 years ago

What is a rule for the sequence 1.8, 2.85, 3.90, 4.95, 6

GalinKa [24]

The rule is add 1.05 because it's 1.8 first then it's 2.85 so you add 1.05 to 1.8 and you will get 2.85. Same with the other numbers.

7 0

3 years ago

The ticket office at Orchestra Center estimates that if it charges x dollars for box seats for a concert, it will sell 50 - x bo

yan [13]

S=50x-x^2

dS/dx=50-2x

d2S/dx2=-2

Since acceleration is a constant negative, when velocity equals zero, it is at the absolute maximum point for S(x)...

dS/dx=0 only when 50-2x=0, 2x=50, x=25

So the price that will maximize income is $25.00 a seat.

And that maximum income is:

S(25)=50x-x^2

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6 0

3 years ago

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Tracey is looking at two different travel agencies to plan her vacation. ABC Travel offers a plane ticket for $295 and a rental

mafiozo [28]

Shirley/Tracey has to stay at least 10 days for the M and N to cost less

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3 years ago

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Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )

Zina [86]

Answer:

$\purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$

Step-by-step explanation:

$\cos( \alpha ) = \frac{ \sqrt{6} }{6} = \frac{1}{ \sqrt{6} } \\ \\ \therefore \: \sin( \alpha ) = \sqrt{1 - { \cos}^{2} ( \alpha ) } \\ \\ = \sqrt{1 - \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} } \\ \\ = \sqrt{1 - {\frac{1}{ {6} }}} \\ \\ = \sqrt{ {\frac{6 - 1}{ {6} }}} \\ \\ \red{\sin( \alpha ) = \sqrt{ { \frac{5}{ {6} }}} } \\ \\ \tan( \alpha ) = \frac{\sin( \alpha ) }{\cos( \alpha ) } = \sqrt{5} \\ \\ \sin( \beta ) = \frac{ \sqrt{2} }{4} \\ \\ \implies \: \cos( \beta ) = \sqrt{ \frac{7}{8} } \\ \\ \tan( \beta ) = \frac{\sin( \beta ) }{\cos( \beta ) } = \frac{1}{ \sqrt{7} } \\ \\ \tan( \alpha - \beta ) = \frac{ \tan \alpha - \tan \beta }{1 + \tan \alpha . \tan \beta} \\ \\ = \frac{ \sqrt{5} - \frac{1}{ \sqrt{7} } }{1 + \sqrt{5} . \frac{1}{ \sqrt{7} } } \\ \\ = \frac{ \sqrt{35} - 1 }{ \sqrt{7} + \sqrt{5} } \\ \\ \purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$

8 0

3 years ago