The possible lengths of the garden would be all of the common factors of 1200.
1 , 1200
2 , 600
3 , 400
4 , 300
5 , 240
6 , 200
7 , 171.43
8 , 150
9 , 133.33
10 . 120
11 . 109.09
12. 100
13. 92.31
14. 85.71
15. 80
16. 75
17. 70.59
18. 66.67
19. 63.15
20. 60
And so on. (all of the above are in pairs)
Veremos que el area del banderín es 930cm^2, entonces la opción correcta es A.
<h3>
¿Que area tiene el banderin?</h3>
Luego de una pequeña busqueda online, pude ver que el banderin es un triangulo isósceles con base de 31cm y altura de 60 cm.
Recordar que para un triangulo de base b y altura h, el area es:
A = b*h/2
Entonces el area del banderín va a ser:
A = (31cm)*(60cm)/2 = 930cm^2
Entonces la opción correcta es A.
Sí quieres aprender más sobre triangulos, puedes leer:
brainly.com/question/2217700
The answer is -8
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Explanation:
There are two ways to get this answer
Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8
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The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4
g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8
Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8
Regardless of which method you use, the answer is -8
Answer:
B.
Step-by-step explanation:
This is vertical reflection, because reflections are made across vertical lines.
