What is pasture?

Perimeter simply represents the sum of all side lengths of a shape. The length of the missing side of the ticket is 5 cm; the length of gold line on each ticket is 20 cm, and 2 bottles of gold ink are required to draw gold lines on 200 tickets.

I've added the image of the ticket as an attachment.

(a) The missing side length

From the attachment, the 4 unknown side lengths are equal. Represent this side length with L.

So, we have:

$Perimeter =2\times 11 + 4 \times L$

This gives

$2\times11 + 4 \times L = 42$

$22 + 4 \times L = 42$

Collect like terms

$4 \times L = 42-22$

$4 \times L = 20$

Divide both sides by 4

$L =5cm$

(b) The length of the gold lines

There are 4 slant lines and the length of one of the slant lines is 5 cm (as calculated above).

So, the length of the gold line is:

$Gold = 4 \times L$

$Gold = 4 \times 5cm$

$Gold = 20cm$

(c) The number of gold ink bottles.

$n = 200$ --- number of tickets

The length of all gold line in the 200 tickets is:

$Length = 200 \times Gold$

$Length = 200 \times 20cm$

$Length = 4000 cm$

$Length = 4000 \times 0.01m$ ---- convert to meters

$Length = 40m$

Given that:

$Bottle = 20m$ --- 1 bottle for 20 m

The number of bottles (n) is:

$n = \frac{Length}{Bottles}$

$n = \frac{40m}{20m}$

$n = 2$

Hence, 2 bottles of gold ink are enough.

Read more about perimeters at:

brainly.com/question/6465134

4 0

2 years ago

An animal shelter has 24 puppies. If the puppies are 32% of the total dog and cat population, how many dogs and cats are in the

34kurt

population *32% = 24

population *.32 = 24

population = 24/.32

population = 75

4 0

2 years ago

A 50-gallon tank is filled with a 40% ethanol solution. How much solution should be drained but and replaced with an 80% ethanol

DIA [1.3K]

How do you create your equations when working on a mixture word problem?

Let's try to think about the general form of a word problem involving mixtures.

In general, we have the following scenario:

a merchant sells two kinds of products (coffee, sweets, etc).

we know the unit prices for both kinds of products and for the final mixture

p

1

US dollars per pound for the first kind of product,

p

2

US dollars per pound for the second kind of product

p

m

US dollars per pound for the mixture

we know the total quantity formed by the mixture of the two products (

q

pounds)

we have to find out the quantities of each product needed to form the mixture

(here we have the variables:

x

denoting the quantity of the first kind of product and

y

denoting the quantity of the second kind of product)

Now, we have sufficient information to work out the equations.

First, we know that the sum of the two quantities is

q

pounds, which gives us the first equation:

x

+

y

=

q

Second, we know that the sale price is the product of quantity and unit price, which gives us the second equation:

p

1

x

+

p

2

y

=

p

m

⋅

q

Now, we have a system of two linear equations that can be easily solved by substitution.

3 0

2 years ago