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3 years ago

What is the function equation and unit rate for this graph?? Help me out! Please!

Mathematics

1 answer:

Thepotemich [5.8K]3 years ago

3 0

Answer:

it 9 girl or boy what ever gender you are your welcome

Step-by-step explanation:

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Li and Jen went shopping. • Li bought 5 pairs of earrings and 1 necklace for a total of $63. • Jen bought 1 pair of earrings and

irina1246 [14]

Answer:

<h2>Earing is $13</h2><h2>Necklace is $10</h2>

Step-by-step explanation:

Firstly, let us express the cost

for Li

5e+n=63---------1

for Jen

e+2n=36---------2

the system of equations are

5e+n=63----1

e+2n=36-----2

Multiply 1 by 1 and 2 by 5 to eliminate e we have

5e+n=63

5e+10n=180

-0-9n=-117

9n=117

Divide both sides by 9 we have

n=117/9

n=13

put n=13 in eqn 1 we have

e+2(13)=36

e+26=36

e=36-26

e=10

Earing is $13

Necklace is $10

5 0

4 years ago

Jane thinks of a number. call it X. She doubles her number, then adds 5 to double the number. What is the number?

Anni [7]

Answer:

4X + 5

Step-by-step explanation:

We start with the unknown number, X.

Doubling the number :

⇒ 2 × X

⇒ <u>2X</u>

<u />

Adding 5 to double the number :

⇒ 2(2X) + 5

⇒ 4X + 5

6 0

3 years ago

How do you do inequalities

fgiga [73]

So some quick tips for inequalities:
**What you do to one side you HAVE TO do it to the other 2**
**If you ever divide a negative number past the inequality signs, the signs FLIP!!**
(e.g. 2>-5x>25)
-2/5 <x < -5

I hope that this has helped!

8 0

3 years ago

Loren drove 200 miles at a certain rate, and his wife, Lois, drove 100 miles at a rate 10 mph slower. If Loren had driven for th

NeX [460]

As long as Loren drove, the law of motion was

$200 = st_1 \implies t_1 = \dfrac{200}{s}$

As long as Loid drove, the law of motion was

$100 = (s-10)t_2 \implies t_2 = \dfrac{100}{s-10}$

So, the total time they took is

$t_1+t_2=\dfrac{200}{s}+\dfrac{100}{s-10}$

Had Loren driven the whole time, the law of motion would have been

$300=st_3 \implies t_3 = \dfrac{300}{s}$

And we know that this time would have been 30 minutes (i.e. 0.5 hours) faster. So, we have

$t_3 = t_1+t_2-0.5$

This translates into

$\dfrac{300}{s}=\dfrac{200}{s}+\dfrac{100}{s-10}-\dfrac{1}{2}$

If we subtract 200/s from both sides, we have

$\dfrac{100}{s}=\dfrac{100}{s-10}-\dfrac{1}{2}$

We can simplify the right hand side by summing the two fractions:

$\dfrac{100}{s-10}-\dfrac{1}{2} = \dfrac{200-(s-10)}{2(s-10)}=\dfrac{210-s}{2(s-10)}$

So, we have to solve

$\dfrac{100}{s}=\dfrac{210-s}{2(s-10)}$

If we cross multiply the denominators, we have

$200(s-10)=s(210-s) \iff 200s-2000=210s-s^2 \iff s^2-10s-2000=0$

Which yields the solutions

$s=-40,\quad s=50$

We accept the positive solution, because the negative would mean to travel backwards, so Loren's rate was 50mph

5 0

3 years ago

Read 2 more answers

PLEASE HELP MARKING BRAINLIEST

xeze [42]

Answer:

a5 =243 x (1/3)^(5-1) = 243x 1/81 =3

Explanation

a(n) = a(1) x r^(n-1)

4 0

3 years ago