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andrew-mc [135]
2 years ago
6

24 students in a class took an algebra test If 18 students passed what percent passed

Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
6 0

Answer: 75%

We know that 1/4 of 24 (25%) is 6, 6 fits into 18 three times and 25 times 3 is 75. So the answer is 75%

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A football team gains 2 yards on the first play, loses 5 yards on the second play, loses 3 yards on the third play, and gains 4
leva [86]

Answer:

A loss of 2 yards

Step-by-step explanation:

2-5-3+4=-2

6 0
3 years ago
Carlita will visit 14 cities
Tanya [424]

Answer:

$52091.95

Step-by-step explanation:

From the given information:

The number of  cities visited = 14

Cost of each cooking demonstration = $3450

The total cost of cooking demonstration = $3450 × 14

= $48300

Book signing material = $1475

∴

The total cost of cooking demonstration and book material is:

= $48300 + $1475 = $49775 ---- (i)

Total meter traveled in visiting 14 cities = 240 * 13 = 3120 miles

However; suppose the weekly rental fee fine = $x  &

the change per mile = $y

Then

y*540 + x = 1188.15    --- (ii)

y*880 + x = 1310.55   --- (iii)

From equation (ii) and (iii)

y *340 = 122.4

y = 122.4/340

y = 0.36

From (ii)

y × 540 + x = 1188.15

(0.36)540 + x = 1188.15

x = 1188.15 - (0.36)540

x = 993.75

Hence, the total cost of travelling by RV camper = $1993.75 + 3120 × (0.36)

= $2116.95

Thus, the total amount the publisher should budget = $49975.0 + $2116.95

= $52091.95

8 0
3 years ago
HELPPPPP MEEEEEEEEEEEEEEEE
Akimi4 [234]

Answer:

V = 20,000 - 2,000t

6 0
3 years ago
Whats 95 closer to 64 or 125
Basile [38]
125-95=30
95-64=31
so it would be 125
6 0
3 years ago
How many eight-digit serial numbers contain three of one digit, two of another digit, two of yet another digit, and one of still
Harlamova29_29 [7]

It is easier to understand the problem if you create a number based on the criteria and then perform the computations. I am going to choose: 111 22 33 4

There are 10 options for the first "1" and only 1 option for the other two 1's

There are 9 remaining options for the first "2" and only 1 option for the other 2

There are 8 remaining options for the first "3" and only 1 option for the other 3

There are 7 remaining options for the "4"

10 x 1 x 1    x      9 x 1     x      8 x 1      x      7

10 x 9 x 8 x 7 = 5,040

Answer: 5,040

6 0
3 years ago
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