The distance covered by the hare and the tortoise in t seconds are 8t and 5t respectively. (Simple Speed-Distance-Time relation)
The tortoise gets a 510m headstart so at t=0 is 1490m.
The functions representing the distance of both of them from the finish line is,
F(x)=2000-8t,. for hare
G(x)=1490-5t,. for tortoise
2x+4y=0
3x+y=10
So what we want to do is get y onto one side by itself using whatever equation you like.
So I'm taking 2x+4y=0 and subtracting 4y from both sides
So we end up with
2x=4y
Divide both sides by four
2/4x is 1/2 x
So we get 1/2x=y
Take this and plug it into the other equation
3x+y=10
3x+1/2x=10
Add your like terms
3 1/2x=10
Putting 3 1/2 as a mixed number we get 7/2
So..
7/2x=10
Multiply by the opposite of 7/2 on both sides
Which is 2/7 this will cancel out the left side.
So we end up with
X= 10•2/7
X=20/7
Which is 2 and 6/7 as a mixed number.
Answer:
3
Step-by-step explanation:
Using the rule of exponents
÷ 
= 
, then
÷ 
= 
= 12³
Tenths is after the decimal so the tenths is 5.
Answer:
![f(x) = 2[\frac{3^x}{9}] + 2](https://tex.z-dn.net/?f=f%28x%29%20%3D%202%5B%5Cfrac%7B3%5Ex%7D%7B9%7D%5D%20%2B%202)
Step-by-step explanation:
Given
Required
Remove the h component
In a function, the h component is highlighted as:
So, we have:
Split the exponents using the following law of indices:
<em>The h component has been removed</em>
Split the exponent using the following law of indices
So, we have:
Express 4^2 as 16
Divide 16 by 2
