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Nataliya [291]
2 years ago
8

What is the initial value of the exponential function shown on the graph?

Mathematics
1 answer:
borishaifa [10]2 years ago
8 0
D. 4 This is where the exponential line on the graph hits the y axis.
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Find the area of each shape, please help and I will give a lot points
Alex73 [517]

Answer:

15. Area of parallelogram = bh

    b = 9m

    h = 4m

    a = 9*4 = 36m^2

   You can also use the rectangle property here.

    a = l*b

    l = 9

    b = 6

    a = 9*6 = 54 m^2

    Though I would prefer the first one better.

16. Area of triangle = 1/2*bh

    b = 17m

    h = 3

    a = 17*3/2 = 51/2 = 25.5m^2

18. Area of a trapezium = a+b/2*h (a and b are two parallel sides and h the            height)

a = 15

b = 7

h = 15

a = 15+7/2*15 = 22/2*15 = 11*15 = 165m^2

19. Area of triangle = 1/2*bh

    b = 24

    h = 7

    a = 24*7/2 = 168/2 = 84

Hope u understood

Please mark as brainliest

Thank You

5 0
2 years ago
The box-and-whisker plot below shows the numbers of text messages received in one day by students in the seventh and eighth grad
Leya [2.2K]
<h3><u>Answer with explanation:</u></h3>

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. Q_1 = 14

Median or second quartile i.e. Q_2 = 18

Third quartile or upper quartile i.e. Q_3 =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. Q_1 = 26

Median or second quartile i.e. Q_2 = 30

Third quartile or upper quartile i.e. Q_3 = 34

and maximum value = 38

a)

The overlap of the two sets of data is as follows.

  • The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.
  • And the maximum value of seventh grade is same as the lower quartile of eighth grade.

b)

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e. Q_3-Q_1

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

c)

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

d)

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

8\times n=12\\\\n=\dfrac{12}{8}\\\\n=\dfrac{3}{2}\\\\n=1.5

Hence, the number is : 1.5

6 0
3 years ago
A biology teacher has developed a new method of teaching chi-square tests to her students. She claims this new method will impro
Illusion [34]

Answer:

A Type I error would occur if there was no evidence of an improvement on the national exam but there really was improvement.

Step-by-step explanation:

A type 1 error simply occurs when we incorrectly reject a true null hypothesis. In the scenario above, An experiment was conducted in other it know if there is sufficient evidence to support a claim that a new teaching method developed improves students score. If this claim is actually true in the real sense. However, after conducting a statistical test, we conuded that there was no sufficient evidence to support her claim of improvement using the new method, hence, the claim was rejected. By rejecting the claim, a true null has been rejected. Hence, a type 1 error has been committed.

7 0
3 years ago
The total cost of renting a banquet hall is a function of the number of hours the hall is rented. The owner of the banquet hall
madam [21]

Answer:

It would be $390 for the 4 hours and the cleaning fees. And the slope would be -13 if you are going from 12 to 7 but would be 13 if you are going from 7 to 12...

Step-by-step explanation:

4 0
2 years ago
Solve the equation by putting it in factored form and using the Zero Product Property: x2 + 12x +11 = 0
nekit [7.7K]

Answer:

janarver 12- mae verdemax x-

Step-by-step explanation:

5 0
2 years ago
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