3 years ago

What is the missing term? Please help me.

Mathematics

1 answer:

Elena-2011 [213]3 years ago

8 0

-2x would be the missing term.

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What is the x & y-intercept of 6x-2y=12

Norma-Jean [14]

Step-by-step explanation:

to find the x intercept make y =0

6x - 2(0) = 12

6x = 12

x= 2

x intercept (2,0)

to find y intercept make x=0

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-2y = 12

0= 12 + 2y

-12 = 2y

y= -6

y intercept (0,-6)

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Answer:

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3 years ago

Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.

alexgriva [62]

Recall that

$|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x$

There are three cases to consider:

(1) When $x+2$ , we have $|x+2|=-(x+2)$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4$

(2) When $x+2\ge0$ and $x-2$ , we get $|x+2|=x+2$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)+(x+2)=4$

(3) When $x-2\ge0$ , we have $|x+2|=x+2$ and $|x-2|=x-2$ , so

$|x-2|+|x+2|=(x-2)+(x+2)=2x$

So

$|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x$