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2 years ago

Solve for y in terms of x

Mathematics

1 answer:

Alika [10]2 years ago

3 0

Answer:

(a) 3 - 2x - 2x² (b) -21

Step-by-step explanation:

given, y +2x² = 3 -2x

make y the subject:

y = 3 - 2x - 2x²

if y = f(x)

then

f(x) = 3 - 2x - 2x²

(b) to find f(3) we need to replace x with 3:

3 - 2(3) - 2*(3)²

-21

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2x-y=1 x-y=-2 ......................................

Mashutka [201]

Answer:

y=5 x=3

Step-by-step explanation:

x-y=-2 move the y over to isolate x

x=-2+y Now plug that in for x in the first equation

2(-2+y)-y=1 Distribute

-4+y=1 Add 4 on both sides

y=5

x-5=-2

x=3

7 0

4 years ago

A salesperson earns a salary of $700 per month plus 2% of the sales. Which inequality correctly represents the total sales if th

Troyanec [42]

Answer:

55000

Step-by-step explanation:

1800 - 700 = 1100

1100 / 0.02 = 55000

4 0

3 years ago

What type of polynomial is 2x+10

Romashka-Z-Leto [24]

AnswerAnswer:

Binomial

Step-by-step explanation:

there are 2 terms

Have a great day!

If it helped mark me as brainliest!

6 0

2 years ago

Read 2 more answers

(√x+1/√x)^2find dy/ dx and substitute 2 in dy/ dx

lions [1.4K]

Hello,
That's better.

I suppose $y=( \sqrt{x} + \dfrac{1}{ \sqrt{x} } )^2 \\

y'=2*( \sqrt{x} + \dfrac{1}{ \sqrt{x} } )*( \dfrac{1}{2 \sqrt{x} } - \dfrac{3}{2x \sqrt{x} } )$

If x=2 then
$y'=2*( \sqrt{2} + \dfrac{1}{ \sqrt{2} } )*( \dfrac{1}{2 \sqrt{2} } - \dfrac{3}{2*2* \sqrt{2} } )\\
=2* \dfrac{2+ \sqrt{2} }{ \sqrt{2} } * \dfrac{1}{4*\sqrt{2} } *(-1)\\
=- \dfrac{2+ \sqrt{2} }{4}$

3 0

3 years ago

I HAVE A CYLINDER AND cone WITH THE

Vlad1618 [11]

Answer:

99 in³

Step-by-step explanation:

Let the radius and height of each be r and h in. respectively.

Write an equation for the volume of cone.

Volume of cone= ⅓πr²h

⅓πr²h= 33

Multiply both sides by 3:

πr²h= 99

Volume of cylinder= πr²h

We have found the value of πr²h previously, which is 99.

Thus, the volume of the cylinder is 99 in³.

6 0

3 years ago