Answer:
m = 0.667
Step-by-step explanation:
Calculate and show the solution for the x-intercept and y-intercept of 4x - 6y = 14.
Calculate the graph plot coordinates for 4x - 6y = 14
Solve 4x - 6y = 14 for x and also for y.
Calculate and show the solution for the slope of 4x - 6y = 14
Find x-intercept
The x-intercept is where the graph crosses the x-axis. To find the x-intercept, we set y1=0 and then solve for x.
4x - 6y = 14
4x - 6(0) = 14
x1 = 3.5 y1 = 0
Find y-intercept
The y-intercept is where the graph crosses the y-axis. To find the y-intercept, we set x2=0 and then solve for y.
4x - 6y = 14
4(0) - 6y = 14
y2 = -2.333 x2 = 0
Get Graph Plot Coordinates
Getting two graph points will allow you to make a straight line on a graph. The plot coordinate format is (x1,y1) and (x2,y2).
Thus, we use the x-intercept and y-intercept results above to get the graph plots for 4x - 6y = 14 as follows:
(x1,y1) and (x2,y2)
(3.5,0) and (0,-2.333)
Find slope
The slope of the line (m) is the steepness of the line. It is the change in the y coordinate divided by the corresponding change in the x coordinate. Simply plug in the coordinates from above and solve for m to get the slope for 4x - 6y = 14
m = (y2 - y1)/(x2 - x1)
m = (-2.333 - 0)/(0 - 3.5)
m = 0.667
hope this is correct! c:
<h3>
Answer: approximately 6.3 miles</h3>
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Explanation:
See the diagram below. The two given angles B = 105 and C = 20 are used to help find angle A
A+B+C = 180
A+105+20 = 180
A+125 = 180
A = 180-125
A = 55
Then we use the law of sines to find the side length c
sin(A)/a = sin(C)/c
sin(55)/15 = sin(20)/c
c*sin(55) = 15*sin(20) ... cross multiply
c = 15*sin(20)/sin(55) .... divided both sides by sin(55)
c = 6.26294249724791 .... value is approximate
c = 6.3 ....... rounding to one decimal place
Between the square roots of 7 and 8, because e^2 is equal to around 7.4, which is between 7 & 8. I hope this helps!
A standard die has numbers = 1,2,3,4,5 and 6
Total outcomes = 6
P = Number of outcomes/Total Outcomes
Even and less than 4 = 1,2,3,4 and 6
P = 5/6
Answered by GauthMath if you like please click thanks and comment thanks
