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dimaraw [331]
3 years ago
9

How do you solve -117=7(3x+4)+2

Mathematics
1 answer:
IrinaVladis [17]3 years ago
6 0
The answer is -7.
-117=7(3x+4)+2= -117=21x+28+2 = 0=21x+147 = -21x=147=-7
You first solve the numbers in the parentheses,add 177 to each side,minus 21 from each side then divide 147 by -21.
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10. Two lighthouses are located on a north-south line.
Kamila [148]

The question is an illustration of bearing (i.e. angles) and distance (i.e. lengths)

The distance between both lighthouses is 5783.96 m

I've added an attachment that represents the scenario.

From the attachment, we have:

\mathbf{\angle A = 180^o - 120^o\ 43'}

Convert to degrees

\mathbf{\angle A = 180^o - (120^o +\frac{43}{60}^o)}

\mathbf{\angle A = 180^o - (120^o +0.717^o)}

\mathbf{\angle A = 180^o - (120.717^o)}

\mathbf{\angle A = 59.283^o}

\mathbf{\angle B = 39^o43'}

Convert to degrees

\mathbf{\angle B = 39^o + \frac{43}{60}^o}

\mathbf{\angle B = 39^o + 0.717^o}

\mathbf{\angle B = 39.717^o}

So, the measure of angle S is:

\mathbf{\angle S = 180 - \angle A - \angle B} ---- Sum of angles in a triangle

\mathbf{\angle S = 180 - 59.283 - 39.717}

\mathbf{\angle S = 81}

The required distance is distance AB

This is calculated using the following sine formula:

\mathbf{\frac{AB}{\sin(S)} = \frac{AS}{\sin(B)} }

Where:

\mathbf{AS = 3742}

So, we have:

\mathbf{\frac{AB}{\sin(81)} = \frac{3742}{\sin(39.717)}}

Make AB the subject

\mathbf{AB= \frac{3742}{\sin(39.717)} \times \sin(81)}

\mathbf{AB= 5783.96}

Hence, the distance between both lighthouses is 5783.96 m

Read more about bearing and distance at:

brainly.com/question/19017345

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Step-by-step explanation:

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