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Serga [27]
2 years ago
5

Find the mean of following data: i)70,30,45,90,45​

Mathematics
1 answer:
mars1129 [50]2 years ago
8 0

Answer:

56

Step-by-step explanation:

The mean is the average number of a data set.

To find the mean:

First, add all the numbers in the data set:

30 + 45 + 45 + 70 + 90 = 280

Next, divide the sum (280) by 5 (amount of values):

280 / 5 = 56

56 represents the mean of your data set.

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]HI THIS MY FAV SONG WHTS URS? WILL GIVE BRAINLIEST
Amiraneli [1.4K]

My favorite song is Make a Wish by NCT U

[Intro]

Oh, ayy

Oh, yeah

[Verse 1]

See you looking right here, don't hesitate (Yeah)

Fully booked up for you, I squeeze in a date (Yeah)

Girl, you got me excited, I wanna play (Ooh)

It’s like I been at sea, the way I been on a wave

(Ayy, ayy, ayy, ayy)

I want you to come join me (Join me)

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Sweet tooth, I eat all of the Skittles

I like my donuts with jam in the middle

You’re a great example of what I'm into

I was thinking we could jam for a little, yeah

[Pre-Chorus]

You'rе all that I want

Let me show what I'm on

[Chorus]

I can do this all night

Back it up, back it up (Yeah)

Yеah, girl, you just my type (Woo)

We should match it up, match it up (We should)

Girl, you're lit, there ain't no one finer

One in a milli', yeah, you light the fire

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It's your birthday, make a wish

[Post-Chorus]

Ooh, you should make a wish

I’ll, I’ll give you anything (Haha), make a wish

Let me do it for you

[Verse 2]

Never take a break, you always workin' overtime

Let’s just run away (Away), memories to make (To make)

You a diamond, see you glowin' in the (Dark)

That's why it's funny when you’re calling me a (Star)

You're my sugar rush, you really got me (Charged)

Really got me charged, you star

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Sweet tooth, I know how to nibble

Ice cream, no flake, lemon drizzle

Chocolate milkshake, just a little

Oreo marshmallow with the sprinkles

[Pre-Chorus]

You're all that I want

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I can do this all night

Back it up, back it up (Back it up on me)

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Girl, your energy, it lifts me high (Lifts me high)

Put my heart and pride on the line (I'll do it for you)

I don't know why it took so long to realize

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I can do this all night

(I can do it, got the cash

You know I like to splash

So throw in a bag)

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Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

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(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

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