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Norma-Jean [14]
3 years ago
10

Solve this question Find AC​

Mathematics
1 answer:
Art [367]3 years ago
6 0

Answer:

26

Step-by-step explanation:

isosceles traingle:

AB=BC

7x-13=x+29

x=7

AC= 3x+5

AC= 3(7)+5

AC= 26

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Joe decides to take his six year old son to the planetarium the price for the child’s ticket it’s $5.75 less than the price for
vovikov84 [41]
Child's ticket x=y-5.75
Adult would be found by solving for y.
x=y-5.75
5.75+x=y-5.75+5.75
5.75+x=y

Y=x+5.75
6 0
3 years ago
Read 2 more answers
Find x if the perimeter of a rectangle is 140. The rectangle has a length of 5x and a width of 4x-2.
RSB [31]

Answer:

x=8

Step-by-step explanation:

p=(l+b)

140=2(x+4x-2)

140=2(9x-2)

140=18x-4

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3 years ago
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zloy xaker [14]
What’s the question??
7 0
3 years ago
Which statement correctly describe the data shown in the scatter plot?
sammy [17]

Answer:

The scatter plot shows a negative association.

Step-by-step explanation:

5 0
2 years ago
Prove: cot(x) sec^4(x) = cot(x) +2tan(x) + tan^3(x)
masha68 [24]
\bf cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\qquad\qquad 
sec(\theta)=\cfrac{1}{cos(\theta)}\quad\qquad  1+tan^2(\theta)=sec^2(\theta)\\\\\\
tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}
\qquad \qquad cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\\\\
-------------------------------\\\\
cot(x)sec^4(x)=cot(x)+2tan(x)+tan^3(x)\\\\
-------------------------------\\\\

\bf \textit{so, let's do the left-hand-side}\\\\
cot(x)sec^2(x)sec^2(x)\implies cot(x)[1+tan^2(x)][1+tan^2(x)]
\\\\\\
cot(x)[1^2+2tan^2(x)+tan^4(x)]
\\\\\\
cot(x)+2tan^2(x)cot(x)+tan^4(x)cot(x)
\\\\\\
cot(x)+2\cdot \cfrac{sin^2(x)}{cos^2(x)}\cdot \cfrac{cos(x)}{sin(x)}+\cfrac{sin^4(x)}{cos^4(x)}\cdot \cfrac{cos(x)}{sin(x)}
\\\\\\
cot(x)+2\cdot \cfrac{sin(x)}{cos(x)}+\cfrac{sin^3(x)}{cos^3(x)}\implies \boxed{cot(x)+2tan(x)+tan^3(x)}
8 0
3 years ago
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