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lutik1710 [3]
2 years ago
11

The area of a triangle is 162 square meters. the height is 18 meters. what is the base

Mathematics
2 answers:
dalvyx [7]2 years ago
3 0
1345533 is the answer because I want points
PtichkaEL [24]2 years ago
3 0

Answer:

Triangle Area = (1/2) * base * height

base = 2 * Area / height

base = (2 * 162) / 18

base = 324 / 18

base = 18 meters

Step-by-step explanation:

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The spaceship must travel 2/3 of a light to get to the moon. Hope this helps!
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Divide the fractions: 2/3 divided by 3/11
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2/3 ÷ 3/11
flip the second one and multiply:
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6 0
3 years ago
Which equation represents a nonlinear function?
Luden [163]
The correct answer is:  [A]:  " <span>x(y – 5) = 2 " .
</span>_____________________________________________________
Consider:
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Choice:  [A]:  " x(y–5) = 2 " ; 

Divide each side by "x" ;

" [x(y – 5)] / x  = 2/x " ; 

  →  y – 5 = 2/x  ;

Add "5" to each side of the equation:

y – 5 + 5 = 2/x + 5 ;

  →  y = 2/x + 5  ;  not a line;  since one cannot divide by "zero" ; there would be no "point" on the graph at "x = 0".  So, this answer choice:  [A] is correct.
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Choice [B]:
 
y -2x -18 = 0 

y - 2x = 18

y = 18 + 2x ;  y = 2x + 18 ; is a line.
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Choice C)  3y + 12 - 6x = 5 ; 

3y = 5 - 12 + 6x ; 

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4 0
3 years ago
Read 2 more answers
A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a stand
Art [367]

Answer:

b. Mean = 1.6 years, standard deviation - 0.92 years, shape: approximately Normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of normal Variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a standard deviation of 4.2 years. Sample of 35:

This means that:

\mu_G = 15

s_G = \frac{4.2}{\sqrt{35}} = 0.71

The distribution of life spans for electric ranges has a mean of 13.4 years and a standard deviation of 3.7 years. Sample of 40:

This means that:

\mu_E = 13.4

s_E = \frac{3.7}{\sqrt{40}} = 0.585

Which of the following best describes the sampling distribution of the difference in mean life span of gas ranges and electric ranges?

Shape is approximately normal.

Mean:

\mu = \mu_G - \mu_E = 15 - 13.4 = 1.6

Standard deviation:

s = \sqrt{s_G^2+s_E^2} = \sqrt{0.71^2+0.585^2} = 0.92

So the correct answer is given by option b.

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3 years ago
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Paladinen [302]
Well what i got was 9/2
4 0
3 years ago
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