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malfutka [58]
2 years ago
11

For what values of r will the area of the shaded region be greater than or equal to 12 square units? Write your answer as an ine

quality.
Mathematics
1 answer:
Soloha48 [4]2 years ago
6 0

Answer:

r>=12

Step-by-step explanation:

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8. Find the value of<br> 8^x/2^y<br> if 3x - y = 4,
tatiyna
Hopes this helps:

Answer: 32

1. Simplify 8^3 to 512.
512 / 2^4

2. Simplify 2^4 to 16.
512 / 16

3. Simplify 513 / 16 to 32.
32
5 0
3 years ago
In the fraction 15⁄7, which of the following is 15? Numerator Divisor Denominator Factor
Colt1911 [192]

Answer is Numerator.

In a fraction, the denominator is on the bottom and the numerator is on top. A factor is a number, when multiplied with another number, that equals the final product. For example: 1, 2, 3, 6, 9, 18 are all factors of 18. A divisor is something you are dividing by in a division problem.

3 0
3 years ago
I need the answer ASAP
MaRussiya [10]

Answer:

11.74

Step-by-step explanation:

I hope this helps you

6 0
3 years ago
Read 2 more answers
Find the surface area of the polyhedron below. The area of each base is 65 cm^2<br>​
yarga [219]

Answer:

D. 290 square cm

Step-by-step explanation:

Surface area of polyhedron

= 2 \times 65 + 7 \times 8 + 4  \times 8 + 3 \times 8 + 3(2 \times 8) \\  = 130 + 56 + 32 + 24 + 48 \\  = 290 \:  {cm}^{2}

8 0
3 years ago
Quadratics: Writing Vertex Form, Algebra 1- Mrs. Daniel, Kuta Software
Oliga [24]
Vertex form is given by:
y=a(x-h)^2+k
where the vertex is (h,k)
7. (h,k)=(-4,1)
plugging in the equation we get:
y=a(x+4)^2+1
but substituting (0,2) in the equation and solving for a we get:
2=a(0+4)^2+1
a=1/16
hence:
Answer: y=1/16(x+4)^2+1

8] 
(h,k)=(2,-4)
thus
y=a(x-2)^2-4
plugging point (3,0) in the eqn and solving for a we get
0=a(3-2)^2-4
0=a-4
a=4
hence;
Answer: y=a(x-2)^2-4

9] (h,k)=(3,3)
thus;
y=a(x-3)^2+3
plugging (2,2) in the equation we get:
2=a(-1)^2+3
a=-1
thus;
Answer: y=-1(x-3)^2+3

10] (h,k)=(-1,-1)
y=a(x+1)^2-1
plugging (0,-3) in the equation and solving for a we get:
-3=a(1)^2-1
a=-2
thus
Answer: y=-2(x+1)^2-1

11] (h,k)=(1,2)
y=a(x-1)^2+2
plugging (0,4) in the equation and solving for a we get:
4=a(-1)^2+2
a=2
thus
y=2(x-1)^2+2

12] (h,k)=(3,-2)
y=a(x-3)^2-2
plugging (2,0) and solving for a we get:
0=a(2-3)^2-2
a=2
thus
t=2(x-3)^2-2
6 0
3 years ago
Read 2 more answers
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