Answer:
x = 30, x = 5 and x = 9
Step-by-step explanation:
The diagonals of a square are perpendicular bisectors of each other, so
∠ AEB = 90° , then
3x = 90 ( divide both sides by 3 )
x = 30
---------------------------------------------------------
(9)
The 4 angles of a square are right and the diagonals bisect the angles, then
∠ BAC = 45° , so
9x = 45 ( divide both sides by 9 )
x = 5
-------------------------------------------------------
(10)
All sides are congruent , so
CD = AB , that is
3x - 5 = 2x + 4 ( subtract 2x from both sides )
x - 5 = 4 ( add 5 to both sides )
x = 9
<u><em>Answer:</em></u>
1)
f(x)→ ∞ when x→∞ or x→ -∞.
2)
when x→ ∞ then f(x)→ -∞
and when x→ -∞ then f(x)→ ∞
<u><em>Step-by-step explanation:</em></u>
<em>" The </em><em>end behavior</em><em> of a polynomial function is the behavior of the graph of as approaches positive infinity or negative infinity. The degree and the leading coefficient of a polynomial function determine the end behavior of the graph "</em>
1)
a 14th degree polynomial with a positive leading coefficient.
Let f(x) be the polynomial function.
Since the degree is an even number and also the leading coefficient is positive so when we put negative or positive infinity to the function i.e. we put x→∞ or x→ -∞ ; it will always lead the function to positive infinity
i.e. f(x)→ ∞ when x→∞ or x→ -∞.
2)
a 9th degree polynomial with a negative leading coefficient.
As the degree of the polynomial is odd and also the leading coefficient is negative.
Hence when x→ ∞ then f(x)→ -∞ since the odd power of x will take it to positive infinity but the negative sign of the leading coefficient will take it to negative infinity.
When x→ -∞ then f(x)→ ∞; since the odd power of x will take it to negative infinity but the negative sign of the leading coefficient will take it to positive infinity.
Hence, when x→ ∞ then f(x)→ -∞
and when x→ -∞ then f(x)→ ∞
Answer:
27
Step-by-step explanation:
4×3=12
9×3=27 if a fraction
4/ would be on the bottom 9/12
Х-100%
36-0,06%
x=(36*100)\0,06=60000
Answer:60000
Alright! We know that the total number of students is 100%. So, if 65% of the students brought a hot lunch, in order to find how many students brought a packed lunch you subtract it from 100%:
[100 - 65] = 35
So 35% of the students brought a packed lunch. Now, in order to find the fraction of students you simply put 35% of students over the total percent of students (100%)"
[35/100]
Then you simply:
[35/100] ⇒ [7/20]
The answer is 7/20ths of the students brought a packed lunch.
More:
Decimal form - .35
Percentage form - 35%
