Multiply r^2+7r+10/3 by 3r-30/r^2-5r-50
<span>=( r^2+7r+10)/3 (3r-30)/(r^2-5r-50) </span>
<span>=(r+2)(r+5)/3 3(r+10)/ (r-10)(r+5) </span>
<span>=3 (r+2)(r+5)(r+10)/3(r-10)(r+5) </span>
<span>=(r+2)(r+10)/(r-10)</span>
Answer: -2/3
Step-by-step explanation:
If you want me to explain just ask.
Answer:
X can be in increments of 1
Y Can be in increments of 5
Answer:(x-3)=-(y-5)=z
Step-by-step explanation:
Given
the point through which line passes is (3,5,0)
so we need a vector along the line to get the equation of line
It is given that line is perpendicular to both i+j & j+k
therefore their cross product will give us the vector perpendicular to both
v=(i+j)\times (j+k)=i-j+k
therefore we get direction vector of line so we can write
=t
i.e.
x=t+3,y=-t+5,z=t