Funtion ! in vertex form is given by
<span>f(x) = 4x^2 + 8x + 1</span> = 4(x^2 + 2x + 1/4) = 4(x^2 + 2x + 1 + 1/4 - 1) = 4(x + 1)^2 + 4(-3/4) = 4(x + 1)^2 - 3
Thus, the least minimun value is (-1, -3)
Also, the least minimum value of function 2 is (-1, 0)
Therefore, function 1 has the least minimum value at (-1, -3)
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Answer and Step-by-step explanation:
The signs didn't really "swap". Instead, the whole function was divided by -1, or we could say the function was divided by -3. That would turn:
-18x² - 15x + 3 = 0
into
(-18 / -3)x² - (15 / -3)x + (3 / -3) = 0
6x² + 5x - 1 = 0
And that gives the "swapped signs".
There are a few you can choose from:
Statistics and probability
Geometry
Proofs
Triangles
Circles
Numerical sequences
Number Theory
etc.
