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GalinKa [24]
3 years ago
12

What is the sum of the rational expression

Mathematics
2 answers:
Pani-rosa [81]3 years ago
7 0

The answer would be B.

Add across : x + 6x = 7x

(x + 1) + (x + 5) = 2x + 6

So you get 7x / 2x + 6

Vinil7 [7]3 years ago
7 0

\bf \cfrac{x}{x+1}+\cfrac{6x}{x+5}\implies \stackrel{\textit{our LCD will be (x+1)(x+5)}}{\cfrac{(x+5)x~~~~+~~~~(x+1)6x}{(x+1)(x+5)}}\implies \cfrac{x^2+5x~~+~~6x^2+6x}{(x+1)(x+5)}
\\\\\\
\cfrac{7x^2+11x}{(x+1)(x+5)}\implies \cfrac{7x^2+11x}{x^2+6x+5}

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Combine like terms 2.4m- 125 + 1.8b+ 92.4​
Brut [27]

Answer:

2.4m+1.8b−32.6

Step-by-step explanation:

Group like terms together

1. 2.4 m + \left( - 125 + 92.4 \right) + 1.8 b2.4m+(−125+92.4)+1.8b

2 . Add or subtract the numbers

2.4 m- 32.6 + 1.8 b2.4m−32.6+1.8b

3 . Rearrange the expression

2.4 m + 1.8 b- 32.62.4m+1.8b−32.6

7 0
3 years ago
Read 2 more answers
a certain atore has a fax machine available for use by its customers. the store charges $2.30 to send the first page and $0.40 f
VikaD [51]
2.30 + 0.40(x - 1) < = 5.10
2.30 + 0.40x - 0.40 < = 5.10
1.90 + 0.40x < = 5.10
0.40x < = 5.10 - 1.90
0.40x < = 3.20
x < = 3.20 / 0.40
x < = 8 <=== 8 pages, at the most, can be faxed

3 0
4 years ago
Pwese<br><br><br> Math suks lol and I didn't learn this
RUDIKE [14]

Answer:

y = 1/9 x z^3

Step-by-step explanation:

y is jointly proportional to x and z^3

y = k * x * z^3 where k is the constant of proportionality

y =12, x = 4 and z =3

12 = k * 4 * 3^3

12 = k * 4 * 27

12 = k * 108

12/108 = k

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8 0
3 years ago
Please help me calculate the volume
vaieri [72.5K]
Multiply base times height and your answer should be without decimals it would be 1,056 with decimals it would be 1.56. Hope this helps!
7 0
3 years ago
How do you find the quadratic function with vertex (-2,5) and point (0,9)?
Anastaziya [24]

Answer: y = (x +2)² + 5

<u>Step-by-step explanation:</u>

y = a(x - h)² + k <em>where "a" is the leading coefficient and (h, k) is the vertex</em>

Since we don't know "a", we need to plug in the point (x, y) and the vertex (h, k) to solve for "a":  (x, y) = (0, 9) and (h, k) = (-2, 5)

y = a(x - h)² + k

9 = a(0 - (-2))² + 5

9 = a(0 + 2)² + 5

9 = a(2)² + 5

<u>-5 </u>   <u>          -5 </u>

4  =  a(4)

<u>÷4 </u>   <u> ÷4   </u>

 1 = a

Next, plug in "a" and the vertex (h, k):

y = a(x - h)² + k

y = 1(x +2)² + 5

y = (x +2)² + 5


6 0
4 years ago
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