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3 years ago

Why does my sister hate me?

Mathematics

1 answer:

Nata [24]3 years ago

8 0

Answer:

Sister Are Like That Sometimes, Give her Time!

Step-by-step explanation:

Bigger siblings- especially girls- love their private time. If your sister seems annoyed, I suggest you just walk away. If she gets upset, agree with her argument. As a bigger sister myself, sometimes we just want nothing more than to be alone. Have you told your parents about this? Siblings need a reminder that they aren't always in charge. Tell your sister that you appreciate her, and that if she ever needs help going through anything, you're there for her. I understand this isn't the easiest, but that's how you can better connect with her.

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14cm

BabaBlast [244]

Answer:

The answer is 336cm

Step-by-step explanation:

Multiply 24 & 14

6 0

2 years ago

Which property of multiplication is used in the multiplication below?

olasank [31]

Zero property because you are using zeros to multiply

4 0

3 years ago

Find the Lateral area of a square pyramid with a slant height of 22m and a base length of 8m

Kay [80]

Answer: 352 $m^{2}$

Step-by-step explanation:

To find the Lateral area of a square pyramid , we will follow the three steps below:

1. Find the perimeter of the base

2. Multiply the perimeter by the slant height

3. Divide the result above by 2

That is :

The lateral surface area of a regular pyramid is lateral area = perimeter of base x slant height of pyramid) ÷ 2.

Applying the formula above:

1. The base is a square , therefore the perimeter of a square is 4L , That is

Perimeter = 4(8)

Perimeter = 32m

2. Perimeter x slant height , that is

32 x 22 = 704m

3. Dividing the result by 2 , we have :

704/2 = 352

Therefore , the Lateral area of the pyramid is 352 $m^{2}$

7 0

3 years ago

What is the answer to x to 50 and 16 to 25 A.32 B.34 C.41

GuDViN [60]

Answer:

A.32

Step-by-step explanation:

We can write a proportion to solve this problem

x 16

------- = ----------

50 25

Using cross products

x*25 = 16*50

Divide each side by 25

25x/25 = 16*50/25

x = 16*2

x = 32

8 0

3 years ago

Read 2 more answers

Evaluate the following integral using trigonometric substitution.

wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ , using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as $asin \theta$ i.e $x = a sin\theta$ .

All integrals in the form $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ are always evaluated using the substitute given where 'a' is any constant.

From the given integral, $\int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx$ where a = 7 in this case.

The substitute will therefore be $x = 7 sin\theta$

2.) Given $x = 7 sin\theta$

$\frac{dx}{d \theta} = 7cos \theta$

cross multiplying

$dx = 7cos\theta d\theta$

3.) Rewriting the given integral using the substiution will result into;

$\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)} } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)} }}} \, 7cos\theta d\theta\\$

$= \int\limits343 cos^{2} \theta \, d\theta$

8 0

3 years ago