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Ksivusya [100]
3 years ago
14

Does anybody know what they mean when for question 3 says evaluate the expression wen c=3? Please help...

Mathematics
1 answer:
alexira [117]3 years ago
6 0
What they mean is plug in 3 for c, so it would be:
2 x 3(3+2) + 4(3+3)
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Is fraction a linear equation​
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NO

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Anyone know how to simplify a whole number into a mixed number or a improper fraction???
AlekseyPX

Answer:

Example any whole number over one would be an improper fraction, so 2=2/1, something like 5/3=1 2/3 would be a mixed number, subtract the numerator by the denominator, how ever many times you can subtract is the whole number and the amount remaining is the numerator, keep the same denominator,,, hope that makes sense

Step-by-step explanation:

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What is the value of (3/10)3
Elenna [48]

Answer:

\frac{9}{10}

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\frac{3}{10}(3)

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\frac{3*3}{10}

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A common error that people make is that they will multiply both the numerator and denominator by the whole number, this is the same as multiplying the answer by (1), thus it is incorrect.

6 0
2 years ago
Suppose that there are five young women and six young men on an island. Each woman is willing to marry some of the men on the is
pochemuha

Answer:

Based on the current information, the last man remaining unmarried will be a choice between two

Jason marries Anna

Matt marries Elizabeth

Kevin marries Barbara

Larry marries Diane

Carol can marry either Nick or Oscar

Step-by-step explanation:

The basic method to sort which woman will be marrying which man is simple.

We have to extract the choice by comparing choices of each woman side by side and then selecting the least common one and hence sorting one by one.

First, let's name all the women and men

1. Anna

2. Barbara

3. Carol

4. Diane

5. Elizabeth

We will refer to them with the initial letter of their name . A for Anna, B for Barbara, C for Carol, D for Diane, E for Elizabeth.

The men :

1. Jason

2. Larry

3. Matt

4. Kevin

5. Oscar

6. Nick

And they will be referred as J for Jason, L for Larry, M for Matt, K for Kevin, O for Oscar  and N for Nick.

Options for A : J , L ,M

Options for B : K, L

Options for C : J, N , O

Options for D : J, L , N , O

Options for E : J, M

As we can see , no one else wants Kevin other than Barbara so :

Kevin marries Barbara

Moving onwards:

Elizabeth can marry either Jason or Matt,

Meanwhile Anna can marry either Jason , Larry or Matt  

Hence,

Matt marries Eilzabeth

as Anna has two more choices still which are Jason and Larry.

Further, seeing the options for Carol and Diane

Carol can marry either Jason, Nick or Oscar while Diane can marry Larry as well as Jason , Nick and Oscar

We can select Jason as the match for Anna as Larry is also a choice for Diane.

Hence, Jason marries Anna

Now we are left with Larry , Nick and Oscar.

Since Carol can only decide from Nick and Oscar but Diane can decide from Larry, Nick and Oscar. Larry is the ideal option for Diane

so, Larry marries Diane

Now in the end, Carol can either choose between Nick or Oscar.

If she chooses Nick to marry, Oscar is left single

If she chooses Oscar to marry, Nick is left single.

7 0
2 years ago
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