Answer:
Answer: x = 33, y = 81..........
3=(1.10)^t
Log(3)=t*log(1.10)
t=log(3)÷log(1.10)
t=11.5 years
<span>A. 9w^33-y^12
B. 18p^15-q^21
C. 36a^22-b^16
D. 64c^15-a^27 -----> 64c^15 = (4c^5)^3; a^27 = (a^9)^3
Answer: D. </span>64c^15-a^27
<h2>
Therefore he took 40 gram of
type solution and 10 gram of
type solution.</h2>
Step-by-step explanation:
Given that , A pharmacist 13% alcohol solution another 18% alcohol solution .
Let he took x gram solution of
type solution
and he took (50-x) gram of
type solution.
Total amount of alcohol =
gram
Total amount of solution = 50 gram
According to problem
⇔![\frac{ [x\times\frac{13}{100}] +[(50 -x) \times\frac{18}{100} ]}{50}= \frac{14}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B%20%5Bx%5Ctimes%5Cfrac%7B13%7D%7B100%7D%5D%20%2B%5B%2850%20-x%29%20%5Ctimes%5Cfrac%7B18%7D%7B100%7D%20%5D%7D%7B50%7D%3D%20%5Cfrac%7B14%7D%7B100%7D)
⇔
⇔- 5x= 700 - 900
⇔5x = 200
⇔x = 40 gram
Therefore he took 40 gram of
type solution and (50 -40)gram = 10 gram of
type solution.