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const2013 [10]
3 years ago
11

If - 4x + 6y = 9 and -2x – 7y = -8 are true equations, what would be the value of -2x + 13y?

Mathematics
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:

  17

Step-by-step explanation:

The expression of interest is the difference of the two given expressions.

  (-4x +6y) -(-2x -7y) = (9) -(-8)

  -2x +13y = 17

The value is 17.

_____

<em>Additional comment</em>

You could go to the trouble to solve the two equations for x and y, then compute the value of the expression you want. As we saw above, that is not necessary.

The first step in problem solving is always "look at the given information and how it relates to what you are asked." A little time spent doing that can save a lot of effort in the actual problem solving process.

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Alex scored 10% in his math test if the test was out of 30, what was his score
Firlakuza [10]

Answer:

Yeesh it was a 3

Step-by-step explanation:

10% of 30=.10 x 30

Answer is 3

5 0
3 years ago
Read 2 more answers
Subract (21x) - (-16 + 7x) can someone help me
koban [17]

The solution to (21x) - (-16 + 7x) is 14x + 16

<h3><u>Solution:</u></h3>

Given that (21x) - (-16 + 7x)

We have to evaluate the given expression

Let's look at the given expression

(21x) - (-16 + 7x)

Multiply the terms within second bracket with minus sign

<em><u>There are two simple rules to remember:</u></em>

  • When you multiply a negative number by a positive number then the product is always negative.
  • When you multiply two negative numbers or two positive numbers then the product is always positive

⇒ (21x) + 16 - 7x

Removing the parenthesis

⇒ 21x + 16 - 7x

Combining the like terms,

⇒ 14x + 16

Thus the solution is 14x + 16

7 0
3 years ago
The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min. If one such class is r
Lady bird [3.3K]

Answer: the probability that the class length is between 50.8 and 51 min is  0.1 ≈ 10%

Step-by-step explanation:

Given data;

lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min

hence, height = 1 / ( 52.0 - 50.0) = 1 / 2

now the probability that the class length is between 50.8 and 51 min = ?

P( 50.8 < X < 51 ) = base × height

= ( 51 - 50.8) × 1/2

= 0.2 × 0.5

= 0.1 ≈ 10%  

therefore the probability that the class length is between 50.8 and 51 min is  0.1 ≈ 10%  

5 0
3 years ago
1) A lake near the Arctic Circle is covered by a 2-meter-thick sheet of ice during the cold winter
Delvig [45]
The answer to your question is c
6 0
3 years ago
Mark dropped an object from a bridge 400 feet above the ground level with an initial velocity of 0. He knows that the gravitatio
lisabon 2012 [21]

Answer:

The first listed equation is the correct equation to solve

The correct answer is: t = 5 seconds

Step-by-step explanation:

Let me mention first that there is an error in the statement that the gravitational pull of the Earth is 16 ft/s^2. It is in fact 32 ft/s^2, and the actual equation uses half of the acceleration multiplied by the square of the variable time, so it gives as final expression :

y(t)=-16\,t^2+ 0 \,t +400

and we want to find the value/s for "t" that make this equation equal zero (when it reaches the ground and the object just touches the ground. This makes the equation we want to solve:

0=-16\,t^2+ 0 \,t +400\\16\,t^2+0\,t -400=0

which solving for "t" becomes:

16\,t^2-400 =0\\16\,t^2=400\\t^2=\frac{400}{16} \\t^2=25\\t= +/- 5\,\,sec

So we adopt the positive answer (positive time) since the negative value has no physical meaning for this problem.

That is: t = 5 seconds

6 0
3 years ago
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