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3 years ago

Given the associated quantity demanded, Q1, and quantity supplied, Q2, which of the following describes the quantity Q2−Q1?

Mathematics

1 answer:

Annette [7]3 years ago

6 0

Answer:

The answer is A. the surplus resulting from the price floor Pc

Step-by-step explanation:

This is because the imposition of a price floor will not cause a shortage.

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What is the combined length of all the buttons longer than 1 inch

muminat

Answer:

$2\frac{1}{2}$ inches

Step-by-step explanation:

The "x" represents the number of buttons.

There are 2 sizes longer than 1 inch:

$1\frac{1}{8}$ in and $1\frac{1}{4}$ in

There are NO 1 1/8 inch buttons

THere are two 1 1/4 inch buttons

Hence the combined length would be:

$1\frac{1}{4}+1\frac{1}{4}=2\frac{2}{4}=2\frac{1}{2}$ inches

5 0

3 years ago

Read 2 more answers

Abe is going to plant 54 oak trees and 27 pine trees. Abe would like to plant the trees in rows that all have the same number of

Virty [35]

Answer:

Step-by-step explanation:

The GCF between 54 and 27 is nine.

4 0

3 years ago

Read 2 more answers

Determine which situation could be represented by the system of linear equations given below

Rudiy27

The answer is
56x-(23y)^9/3 = 42

7 0

3 years ago

Find the area of the figure to the nearest tenth

schepotkina [342]

Answer:

Step-by-step explanation:

This is a sector of a circle measuring 140° and the circle has radius 9 inches.

We can use the formula for the area sector of a circle to figure this out.

Area of a Sector of a Circle = $\frac{\theta}{360}*\pi r^2$

Where

$\theta$ is the intercepted angle (here it is 140), and

r is the radius (here it is 9)

<em>plugging into the formula, we get:</em>

<em> $A=\frac{\theta}{360}*\pi r^2\\=\frac{140}{360}*\pi (9)^2\\=\frac{7}{18}*81\pi\\=98.96$ </em>

rounding to nearest tenth, it is 99.0 inches squared.

Option A is right.

7 0

4 years ago

What is the solution(s) to f(x) = g(x), where f(x) = x^2−2 and g(x) = 5x − 8

babymother [125]

If f(x)=g(x), than x²-2=5x-8

Now we need to solve this equation

$x^2-2=5x-8\\x^2-5x+6=0\\D=b^2-4ac=(-5)^2-4\times6=25-24=1=\sqrt{1} ^2\\x_1=\dfrac{5+1}{2}=3\\ x_2=\dfrac{5-1}{2} =2$

Answer: 2, 3

5 0

4 years ago