I dont know I'm sorry
Step-by-step explanation:
Answer:Behest
Step-by-step explanation:
1. This is a very easy question as you can just plug in 2 x-values and get the y-value, run a line through it, and you are done.
For example,
x = 2t
x = 2(2) = 4
x = 2(3) = 6
Now, you know there are points at (2, 4) and (3, 6).
2. This one is a little tricky, but all it's saying is that it has a specified domain. The parametric equation only works for values -2 ≤ t ≤ 3. So, you can do the exact same thing, except your line will only exist for points through the x-values -2 and 3. Let's plug in numbers:
y = t + 5
y = -2 + 5 = 3
y = 1 + 5 = 6
Now you know that this line runs through (-2, 3) and (1, 6). Remember, your line starts at -2 and ends at 3. It can't go any further than that.
Im unable to send the equation
For this case we have the following expression:
(ab) ^ - 2
Rewriting the expression we have:
(ab) ^ - 2 = 1 / (ab) ^ 2
Then, for power properties we have:
1 / (ab) ^ 2 = 1 / (a ^ 2b ^ 2)
Answer:
The simplified expression is:
1 / (a ^ 2b ^ 2)