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Andrej [43]
2 years ago
9

Find the zeros of ƒ(x) = x3 + 6x2 + 8x.

Mathematics
2 answers:
EleoNora [17]2 years ago
5 0

x^3+6x^2+8x = 0\\\\\implies x^3+2x^2 +4x^2+8x =0\\\\\implies x^2(x+2)  +4x (x+2)   =0\\\\\implies (x+2)(x^2 +4x) = 0\\\\\implies x (x+2) (x+4)=0\\\\\text{Hence,} \\\\x = 0 ,-2,-4

Softa [21]2 years ago
3 0

Answer:

Option A: x=0, x=-2, and x=-4

Step-by-step explanation:

f(x)=x^3+6x^2+8x

0=x^3+6x^2+8x

0=x(x^2+6x+8)

0=x(x+2)(x+4)

x=0, x=-2, and x=-4

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Now the equation is 20=8+36+12x
Now, bring all numbers without variables on the left side

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Now simplify

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Hope this helped!!! :D
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