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3 years ago

Find the zeros of ƒ(x) = x3 + 6x2 + 8x.

2 answers:

5 0

$x^3+6x^2+8x = 0\\\\\implies x^3+2x^2 +4x^2+8x =0\\\\\implies x^2(x+2) +4x (x+2) =0\\\\\implies (x+2)(x^2 +4x) = 0\\\\\implies x (x+2) (x+4)=0\\\\\text{Hence,} \\\\x = 0 ,-2,-4$

Softa [21]3 years ago

3 0

Answer:

Option A: $x=0$ , $x=-2$ , and $x=-4$

Step-by-step explanation:

$f(x)=x^3+6x^2+8x$

$0=x^3+6x^2+8x$

$0=x(x^2+6x+8)$

$0=x(x+2)(x+4)$

$x=0$ , $x=-2$ , and $x=-4$

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Which of the following are like terms?

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3 years ago

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Mr. Osterhout is putting trim around the edge of a circular merry-go-round that has a diameter of 15 feet. How much trim does he

Lubov Fominskaja [6]

Given:
circular merry-go-round that has a diameter of 15 feet.

Find: How much trim does he need to buy to put around the edge of the merry-go-round?

We need to find the circumference of the merry-go-round to get the measurement of the trim needed.

Circumference = π d
π = 3.14
d = diameter = 15 feet

Circumference = 3.14 * 15 feet
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Mr. Osterhout needs to buy 47.10 feet of trim to put around the circular merry-go-round.

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3 years ago

An equation parallel and perpendicular to 4x+5y=19

UNO [17]

Answer:

Parallel line:

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

$y=\frac{5}{4}x-\frac{1}{2}$

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

$4x+5y=19$

we can change it into y=mx+b form

$5y=-4x+19$

$y=-\frac{4}{5}x+\frac{19}{5}$

so,

$m=-\frac{4}{5}$

Parallel line:

we know that slope of two parallel lines are always same

so,

$m'=-\frac{4}{5}$

Let's assume parallel line passes through (1,1)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-1=-\frac{4}{5}(x-1)$

now, we can solve for y

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

$m'=\frac{5}{4}$

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-2=\frac{5}{4}(x-2)$

now, we can solve for y

$y=\frac{5}{4}x-\frac{1}{2}$

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3 years ago

Dexter has 83 tiles left over from tiling his bathroom floor and he would like to use them to tile the front entrance of his hou

creativ13 [48]

Answer: [0, 396]

Step-by-step explanation:

The domain is the acceptable values of x in the function. In this case, x = t, the number of tiles. If you think about it, the minimum number of tiles is 0 (you can't have a negative number of tiles), and the maximum number of tiles is 44 (you only have 44 tiles). So, the domain for this function is from 0 to 44.

0 to 44 written in interval notation is [0,44].

The range is the acceptable values of y in the function. In this case, y = A, the area given. A(t) = 9t, so you can use the acceptable values of t to get the range. Again, the minimum area is 0 because you can't have negative area. To find the maximum area, plug in the maximum number of tiles: 9.

A(t) = 9t

A = 9(44)

A = 396

With the maximum number of tiles, 44, the area you get is 396 cm². Therefore, the acceptable values of A are from 0 to 396.

0 to 396 written in interval notation is [0, 396].

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3 years ago

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dangina [55]

Answer:

Step-by-step explanation:

Its 19

9+10 is 19

Yeah

im just putting random words so it'll let me post this

7 0

2 years ago

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