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Lelu [443]
3 years ago
6

Can someone help me with this one question

Mathematics
2 answers:
Ludmilka [50]3 years ago
8 0
Idk hahah but an i dont know that shift
erma4kov [3.2K]3 years ago
4 0
Second option is the correct one
a1 = 37 \\ an = a(n - 1) - 11
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In a prison, Prison A, prisoners get 2 visits consisting of 4 hours every year. In another prison, Prison B, prisoners get 1 vis
pochemuha
The answer is Prison A :)
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3 years ago
30 POINTS TO ANSWER!!!!!
Ede4ka [16]

Answer:

35

y = -4(-8) +3

y= 35

yea

that is the out put so 35

3 0
3 years ago
Part 1 - Application Pick one of the two graphs below. Describe a situation which could be modeled by this polynomial graph. Be
Goryan [66]

One good example of a situation that can be modeled by this Polynomial Graph is the price-time relationship between currency pairs being traded on the Foreign Exchange Market.

<h3>What is a Polynomial Graph?</h3>

A polynomial parameter graph is essentially a smooth continuous curve.

Although the forex graph attached has sharp undulations, when regressed and viewed via Polynomial Regression Indicators, they exhibit strong polynomial qualities that meet the requirements of the definition above.

It is to be noted that the Y-Axis is indicative of the price of the currency pairs (which could be any currency against another) and the X-Axis expresses time. See the attached graphs for a better picture.

Learn more about polynomial graphs at:
brainly.com/question/9696642
#SPJ1

6 0
2 years ago
There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that pl
insens350 [35]

We're told that

P(A\cap B)=0.15

P(A\cup B)^C=0.06\implies P(A\cup B)=0.94

P(B\mid A)=P(B^C\mid A)=0.5

where the last fact is due to the law of total probability:

P(A)=P(A\cap B)+P(A\cap B^C)

\implies P(A)=P(B\mid A)P(A)+P(B^C\mid A)P(A)

\implies 1=P(B\mid A)+P(B^C\mid A)

so that B\mid A and B^C\mid A are complementary.

By definition of conditional probability, we have

P(B\mid A)=P(B^C\mid A)

\implies\dfrac{P(A\cap B)}{P(A)}=\dfrac{P(A\cap B^C)}{P(A)}

\implies P(A\cap B)=P(A\cap B^C)

We make use of the addition rule and complementary probabilities to rewrite this as

P(A\cap B)=P(A\cap B^C)

\implies P(A)+P(B)-P(A\cup B)=P(A)+P(B^C)-P(A\cup B^C)

\implies P(B)-[1-P(A\cup B)^C]=[1-P(B)]-P(A\cup B^C)

\implies2P(B)=2-[P(A\cup B)^C+P(A\cup B^C)]

\implies2P(B)=[1-P(A\cup B)^C]+[1-P(A\cup B^C)]

\implies2P(B)=P(A\cup B)+P(A\cup B^C)^C

\implies2P(B)=P(A\cup B)+P(A^C\cap B)\quad(*)

By the law of total probability,

P(B)=P(A\cap B)+P(A^C\cap B)

\implies P(A^C\cap B)=P(B)-P(A\cap B)

and substituting this into (*) gives

2P(B)=P(A\cup B)+[P(B)-P(A\cap B)]

\implies P(B)=P(A\cup B)-P(A\cap B)

\implies P(B)=0.94-0.15=\boxed{0.79}

8 0
3 years ago
If the two prisms have equal heights and volumes, what is the length of the x in Polam I?
anastassius [24]

Answer:

A

Step-by-step explanation:

Because it is same height

3 0
3 years ago
Read 2 more answers
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