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2 years ago

What is the length of the hypotenuse? If necessary, round to the nearest tenth.

Mathematics

2 answers:

qwelly [4]2 years ago

8 0

Answer:

The length of the hypotenuse is 17 km.

Step-by-step explanation:

Since this is a right triangle, we can use Pythagoras theorem to solve for c.

c² = 15² + 8²
=> c² = 225 + 64
=> c² = 289
=> c = 17

Hence, the length of the hypotenuse is 17 km.

Hoped this helped.

$BrainiacUser1357$

artcher [175]2 years ago

6 0

Answer:

17 kilometers

Step-by-step explanation:

The pythagorean theorm is a^2 + b^2 = c^2

In this problem we can call 8 km a and 15 km b.

Plug 8 and 15 into the pythagorean theorm to get 8^2 + 15^2 = c^2

This will give you 289=c^2

Take the square root of both sides to get c=17

Hope this helps!

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Answer:

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Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Part a

For this case we define the random variable X="number of car owners in a random sample of 12 who get the maintenance service done on their cars according to the schedule recommended by the auto company". And for this case the distribution for X is:

$X \sim Binom (n =12, p=0.18)$

And the possible values for the random variable are X=0,1,2,3,4,5,6,7,8,9,10,11,12

Part b

Find to 3 decimal places the probability that exactly 3 car owners in a random sample of 12 get the maintenance service done on their cars according to the schedule recommended by the auto company.

Using the probability mass function we got:

$P(X=3)=(12C3)(0.18)^3 (1-0.18)^{12-3}=0.21506$

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