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malfutka [58]
3 years ago
6

Alice works at a health care facility. She has measured the hemoglobin levels of 200 people. The data follows a normal distribut

ion with a mean of 14 g/dL and a standard deviation of 1. From the given data, we can conclude that about people have hemoglobin levels less than 13, and about people have hemoglobin levels greater than 14.
Mathematics
1 answer:
rewona [7]3 years ago
5 0
Since the data follows a normal distribution, the 68-95-97 rule can be used to describe the number of people falling under N standard deviations from the mean. Since the standard deviation is 1, hemoglobin levels of 13 -15 g/dL contains 68% of the sample, or 136 people. This means the 32 people have less than 13 g/dL and 32 people have more than 15 g/dL.
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Actually, what you said you have so far is not correct.  The 2 correct answers are the 1st one (x + y = 15) and the 5th one (15x + 10y > 180)

Step-by-step explanation:

If tutoring French is x hours and scooping ice cream is y hours and he is going to work 15 hours for sure doing both, then we can add them together to get that x hours + y hours = 15 hours, or put simply:  x + y = 15.

Now we are going to throw in the added fun of the money he makes doing each.  The thing to realize here is that we can only add like terms.  So looking at the equation above, we have x hours of tutoring and y hours of scooping, so if we want to add them, we will add those number of hours together to get the total number of hours he worked, which we know to be 15.  The same goes for money.  If we add money earned from tutoring to money earned from scooping, we need that to be greater than the money he wants to earn which is 180 at least.  Because he wants to earn MORE than $180. we use the ">" sign.  Since he earns $15 an hour tutoring, that expression is $15x; since he earns $10 an hour scooping, that expression is $10y.  Now add them together (and you CAN because they are both expressions relating dollars to dollars) and set the sum > $180:

$15x + $10y > $180.  That's why your answer is not correct.  Use mine (with the understanding that you care about why yours is wrong and mine is correct) and you'll be fine.

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