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Goryan [66]
2 years ago
12

How to find a value of ex2

Mathematics
1 answer:
Natalija [7]2 years ago
8 0
Can you tell the real question this doesn't make sense
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) For which values of x is f '(x) zero? (Enter your answers as a comma-separated list.) x = (No Response) For which values of x
grigory [225]

Answer:

Check below, please

Step-by-step explanation:

Step-by-step explanation:

1.For which values of x is f '(x) zero? (Enter your answers as a comma-separated list.)

When the derivative of a function is equal to zero, then it occurs when we have either a local minimum or a local maximum point. So for our x-coordinates we can say

 f'(x)=0\: at \:x=2, and\: x=-2

2. For which values of x is f '(x) positive?

Whenever we have  

 f'(x)>0

then function is increasing. Since if we could start tracing tangent lines over that graph, those tangent lines would point up.

 f'(x)>0 \:at [-4,-2) \:and\:(2, \infty)

3. For which values of x is f '(x) negative?  

On the other hand, every time the function is decreasing its derivative would be negative. The opposite case of the previous explanation. So

 f'(x)

4.What do these values mean?

 f(x) \:is \:increasing\:when\:f'(x) >0\\\\f(x)\:is\:decreasing\:when f'(x)

5.(b) For which values of x is f ''(x) zero?

In its inflection points, i.e. when the concavity of the curve changes. Since the function was not provided. There's no way to be precise, but roughly

at x=-4 and x=4

6 0
3 years ago
Find the annual rate of interest. Principal = 4600 rupees, Period = 5 years, Total amount = 6440 rupees, Annual rate of interest
Len [333]

The annual rate of interest per year is 8%

<u>Solution:</u>

Given:- Principal (p) = 4600 rupees, Time –Period (t) = 5 years, Total amount(A) = 6440 rupees

First we will calculate the Interest and then using formula of simple interest we will calculate the rate of interest

Interest = Amount – Principal

Interest = 6440  – 4600 = 1840

Now using the formula of simple Interest and on putting values we get,

\text {Simple Interest }=\frac{P \times R \times T}{100}

Where "P" is the principal and "R" is the rate of interest per annum and "T" is the time period

1840=\frac{4600 \times R \times 5}{100}

\begin{aligned} \mathrm{R} &=\frac{1840 \times 100}{4600 \times 5} \\\\ \mathrm{R} &=\frac{1840}{230} \\\\ \mathrm{R} &=8 \% \end{aligned}

Hence, the required rate of interest per year is 8%

6 0
3 years ago
I will give.help please
Rudik [331]

Answer:

74.94×10^3= 74940 because the number 10³ has 3 zeros when it is written without an exponent.

Step-by-step explanation:

when times 10, you move the decimal point to the right.

6 0
2 years ago
Read 2 more answers
Solve 7k÷3=21<br><br><br> The solution is k __
qaws [65]
First, multiply by 3 on both sides:
7k = 63

Divide by 7:
k = 9

So, k = 9
4 0
2 years ago
Read 2 more answers
Mr. Herman's class is selling candy for a school fundraiser. The class has a goal of raising $500 by selling C
katovenus [111]

Answer:

2.75 x (c) = 500

Step-by-step explanation:

i think this is it

8 0
2 years ago
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