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Nata [24]
2 years ago
5

Mackenzie needed to get her computer fixed. She took it to the repair store. The technician at the store worked on the computer

for 3.75 hours and charged her $157 for parts. The total was $400.75. Write and solve an equation which can be used to determine x, the cost of the labor per hour.
Mathematics
1 answer:
Ann [662]2 years ago
6 0

Answer:

x=65

Step-by-step explanation:

Based on the given conditions, formulate: 157+3.75 X x=400.75

Rearrange unknown terms and Calculate the sum:

3.75x = 400.75 - 157

3.75x = 243.75

x=243.75 / 3.75

x=65

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Nataly [62]
1/4 trust me bro just took it
5 0
3 years ago
The time it takes you to get to campus varies inversely as your driving rate. averaging 20 miles per hour in terrible​ traffic,
Korvikt [17]
Given that the time taken to get to campus is inversely proportional to driving rate, let the time be t and rate be r, thus the function will be written as:'
t=k/r
where
k is the constant of proportionality given by:
k=tr
when r=20 mph, t=1.25 hrs
thus
k=20×1.25
k=25 miles
thus the formula is:
t=25/r
when r=55 mph, the value of t will be:
t=25/55
t=5/11 hours

3 0
3 years ago
student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te
alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = \frac{1}{4}.

Thus, the probability that the student does not receive version A = 1-\frac{1}{4} = \frac{3}{4}.

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}

= (\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5

= (\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]

= (\frac{3}{4^4})[1+\frac{1}{16}]

= (\frac{3}{256})[\frac{17}{16}]

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0
3 years ago
Tell whether the given number is a solution of each question. ( Must show work for credit)
guajiro [1.7K]

Answer/Step-by-step explanation:

1. 9 = 2a + 3 ; 3

Let's solve for a.

9 - 3 = 2a (subtraction property of equality)

6 = 2a

\frac{6}{2} = a (division property of equality)

3 = a

a = 3

Therefore, 3 is a solution to 9 = 2a + 3

2. 5n - (-30) = 5 ; 7

5n + 30 = 5 (- × - = +)

5n = 5 - 30 (Subtraction property of equality)

5n = -25

\frac{5n}{5} = \frac{-25}{5} (division property of equality)

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Therefore, 7 is not a solution of 5n - (-30) = 5

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4.4r = 1.6 + 2.8

4.4r = 4.4

\frac{4.4r}{4.4} = \frac{4.4}{4.4}

r = 1

Therefore, 1 is a solution of 4.4r - 2.8 = 1.6.

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He spent 27.7 repeating minutes of his class talking.
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3 years ago
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