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Serga [27]
3 years ago
14

A rectangle has a length of x + 2, a width of 7, and a perimeter of 32. The value of x is

Mathematics
1 answer:
DanielleElmas [232]3 years ago
3 0
2 (x + 2) + 2 (7) = 32

2x + 4 + 14 = 32

2x + 18 = 32

2x = 32 - 18

2x = 14

2x ÷ 2 = 14 ÷ 2

x = 7
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Record the following data in the circle graph 25% of the people like science the best ,half of the people like math the best, 25
uysha [10]

Answer:

ok so it would be square root 2

Step-by-step explanation:

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2 years ago
how many meatballs are required fora party of 10 adults and 5 childen? fomual is m=4a+2 where c= children and m=meatball and a=
professor190 [17]
The answer is 42 because there are 10 adults and
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3 0
3 years ago
A person places $37700 in an investment account earning an annual rate of 5%,
lorasvet [3.4K]

Answer:

8,229,437 cents

Step-by-step explanation:

Using the compound interest formula;

A = P(1+r)^n

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Principal invested = $37700

rate r = 5% = 0.05

Time t = 16years

Substitute into the formula

A = 37700(1+0.05)^16

A  = 37700(1.05)^16

A = 37700(2.1829)

A = 82,294.37

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4 0
3 years ago
A milligram is what fraction of a kilogram
pishuonlain [190]
The answer is 1/1000000
4 0
3 years ago
Find the equation of the line perpendicular to y =<br> 3x + 6 and containing the point (-9,-5).
neonofarm [45]

The equation of the line perpendicular to y =  3x + 6 and containing the point (-9,-5) is y = \frac{-1}{3}x - 8

<em><u>Solution:</u></em>

Given that line perpendicular to y =  3x + 6 and containing the point (-9, -5)

We have to find the equation of line

<em><u>The slope intercept form is given as:</u></em>

y = mx + c  ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

<em><u>Let us first find the slope of line</u></em>

The given equation of line is y = 3x + 6

On comparing the given equation of line y = 3x + 6 with eqn 1, we get,

m = 3

Thus the slope of given equation of line is 3

We know that <em>product of slopes of given line and slope of line perpendicular to given line is equal to -1</em>

Slope of given line \times slope of line perpendicular to given line = -1

3 \times \text{ slope of line perpendicular to given line }= -1

\text{ slope of line perpendicular to given line } = \frac{-1}{3}

Let us now find the equation of line with slope m = \frac{-1}{3} and containing the point (-9, -5)

Substitute m = \frac{-1}{3} and (x, y) = (-9, -5) in eqn 1

-5 = \frac{-1}{3}(-9) + c\\\\-5 = 3 + c\\\\c = -8

<em><u>Thus the required equation of line is:</u></em>

Substitute m = \frac{-1}{3} and c = -8 in eqn 1

y = \frac{-1}{3}x - 8

Thus the required equation of line perpendicular to given line is found

6 0
3 years ago
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