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2 years ago

4. A straight line passes through points (3, 12) and (7,4). What is the equation of the line?

Mathematics

2 answers:

jeyben [28]2 years ago

6 0

Answer:

slope is -2 (-8/4)

point slope formula y=y1=m(x-x1) m slope (x1, y1) point

y-4=-2(x-7)

y=-2x+18

Arte-miy333 [17]2 years ago

4 0

Answer:

y=-2x+18

Step-by-step explanation:

Since the y-value is going down, we can assume that the line is going negative. As the midpoint is (5, 8), you should subtract 2 units from 3 and 4 units from 12 to get (1, 16) and therefore to get to (-1, 20), since the y-intercept is 18, the slope is 2, and it is going negative, your final answer is y=-2x+18.

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Which function has a range of y<3? y=3(2) y=2(3) O y=-(2)* +3 O y= (2)* - 3

VARVARA [1.3K]

option C is correct.

Step-by-step explanation:

If a function is defined as

$f(x)=a^x$ where, a>0, then the range of the function is greater than 0.

$a^x>0$ .... (1)

Option A: Using inequity (1),

$2^x>0$

Multiply both side by 3.

$3(2^x)>0$

The range of first function is y>0. Therefore option A is incorrect.

Option B: Using inequity (1),

$3^x>0$

Multiply both side by 2.

$2(3^x)>0$

The range of second function is y>0. Therefore option B is incorrect.

Option C: Using inequity (1),

$2^x>0$

Multiply both side by -1.

$-2^x$

Add 3 on both the sides.

$-2^x+3$

$y$

The range of first function is y<3. Therefore option C is correct.

Option D: Using inequity (1),

$2^x>0$

Subtract 3 from both the sides.

$2^x-3>-3$

$y>-3$

The range of second function is y>-3. Therefore option D is incorrect.

7 0

3 years ago

Its easy please ill give brainiest dont guess

valentina_108 [34]

Answer:

I don't know

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

7x^2=9+x what are the values of x Will give medal and points

DENIUS [597]

7x² = 9 + x Subtract x from both sides
7x² - x = 9 Subtract 9 from both sides
7x² - x - 9 = 0 Use the Quadratic Formula

a = 7 , b = -1 , c = -9

x = $\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ Plug in the a, b, and c values
x = $\frac{- (-1) \pm \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}$ Cancel out the double negative
x = $\frac{1 \pm \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}$ Square -1
x = $\frac{1 \pm \sqrt{1 - 4(7)(-9)} }{2(7)}$ Multiply 7 and -9
x = $\frac{1 \pm \sqrt{1 - 4(-63} }{2(7)}$ Multiply -4 and -63
x = $\frac{1 \pm \sqrt{1 + 252} }{2(7)}$ Multiply 2 and 7
x = $\frac{1 \pm \sqrt{1 + 252} }{14}$ Add 1 and 252
x = $\frac{1 \pm \sqrt{253} }{14}$ Split up the $\pm$
x = $\left \{ {{ \frac{1 + \sqrt{253} }{14} } \atop { \frac{1 - \sqrt{253} }{14} }} \right.$
The approximate square root of 253 is 15.905973.
x ≈ $\left \{ { \frac{1 + 15.905973}{14} } \atop { \frac{1 - 15.905973}{14} }} \right$ Add and subtract
x ≈ $\left \{ {{ \frac{16.905973}{14} } \atop { \frac{14.905973}{14} }} \right.$ Divide
x ≈ $\left \{ {{1.2075} \atop {1.0647}} \right.$ Round to the nearest hundredth
x ≈ $\left \{ {{1.21} \atop {1.06}} \right.$

7 0

3 years ago

Let ƒ(x) = x + 1 and g(x) = 5x. Evaluate the composition (ƒ ∘ g)(–1). Question 2 options: A) (ƒ ∘ g)(–1) = 6 B) (ƒ ∘ g)(–1) = –4

Papessa [141]

Answer:

answer B

Step-by-step explanation:

hello,

$f(x)=x+1\\g(x)=5x \ \ so\\(fog)(-1)=f(g(-1))=f(-5)=-5+1=-4$