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3 years ago

8

A table is 3 feet wide. The length of the table can be adjusted as needed. You need at least 24 square feet of space on the tabl

e. Write and solve an inequality to represent the minimum length the table should have. (Please solve due in 15 mins)

1 answer:

joja [24]3 years ago

7 0

Answer: try photo math

Step-by-step explanation:

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Express 0.234 234 .................. as a fraction in its simplest form

KIM [24]

Let n = .234....

Now our job is to get the entire part that repeats on the left of the decimal point.
If we multiply the number by 1000 exactly one 2, one 3 and one 4 will move to the left.

So 1000n = 234.234... now lets remove our original number
-<u> n = -.234...</u> Notice how all the repeaters minus all the repeaters
999n = 234 leaves only the 234 that we move to the left of
the decimal point
Now lets divide both side by 999
<u>999n </u> = <u>234
</u>999 999 this is the answer in unreduced form 9 can go into both = <u>26</u><u>
</u> 111
<u />
Try it on your calculator (divide 26 by 111)

3 0

3 years ago

Rewrite the sum of 30 and 42 by factoring out of the greatest common factor

kvasek [131]

Answer:

12

Step-by-step explanation:

Factors of 30: 1,2,3,5,(6),10,15,30

Factors of 42: 1,2,3,(6),7,14,21,42

30 divided by 6, 42 divided by 6

(5) + (7)= 12

8 0

3 years ago

2y² - 9y - 2 + 4 (y + 1) =

Nuetrik [128]

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$2 {y}^{2} - 9y - 2 + 4(y + 1) =$

$2 {y}^{2} - 9y - 2 + 4y + 4 =$

$2 {y}^{2} - 9y + 4y - 2 + 4 =$

Collect like terms

$2 {y}^{2} - 5y + 2 =$

$(2y - 1 )(y - 2)$

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3 0

3 years ago

Read 2 more answers

I have six equal tiles one was yellow and three tiles are purple what fraction of the tiles are yellow or purple.

Sphinxa [80]

5/6 tiles

hope this helps!!!

5 0

3 years ago

Suppose a box contains a double-headed coin, a double-tailed coin, and a conventional coin. A coin is picked at random and flipp

notsponge [240]

Answer:

P(D|A)=0.666

Step-by-step explanation:

We will use the tree diagram to understand these probabilities that is attached to the bottom of this answer.

Since there are three coins in the box, the probability of taking one in particular (the double-headed one, which is event D) is one third, which is equal to 0.333

Since the coin showed heads, the probability of it being a double-tailed coin is zero.

The Bayes theorem says that P(D|A) is the multiplication of P(D) and P(A), divided the probability of A happening by any means, happening D or not, which is the sum of all probabilities of A happening:

$P(D|A)=\frac{P(D)*P(A_1)}{P(D)*P(A_1)+P(E)*P(A_2)} =\frac{0.333*1}{0.333*1+0.333*0.5}=0.666$

5 0

3 years ago