If the width of the cardboard = x cm then its length is given by x + 8 cm.
Then the length of the box will be x + 8 - 2(2) = x + 4
and the width = x - 2(2) = x - 4 cm The height is 2 cm
Volume = h*w*l = 2(x - 4)(x + 4) = 256
2(x^2 - 16) = 256
x^2 - 16 = 128
x^2 = 144
x = 12 cm
Dimensions of the box are:-
length = 12 + 4 = 16cm
width = 12 - 4 = 8 cm
height = 2 cm
Let us solve for the total area. In this problem, we solve area 1 (the rectangle in the middle) and the area 2 ( the two half circle on the sides).
Solve for area 1:
Area rec = L * W = 5units * 4 units = 20 squared units
Solve for area 2:
Area cir = pi *r² = 3.14 * (2 units)² = 12.56 squared units
Total area = 20 + 12.56 = 32.56 foot²
Total cost = 32.56 foot² * ($23/foot²) = $ 748.88
Total cost is $748.88.
Hello,
Equation is y=k(x-1)²-9
and when x=0,y=-6==>-6=k*1²-9==>k=3
y=3(x-1)²-9
when y=0, 3(x-1)²-9=0
==>(x-1-√3)(x-1+√3)=0
x-intercepts are (1+√3,0) and (1-√3,0)
Answer B.
The answer is 60. You can find this out by finding the least common multiple of 10 and 12, which is 60 because 10x6=60 and 12x5=60. Hope this helps :)
Yes because,
8×1 = 8
8×2 = 16
8×3 = 24
8×4 = 32
8×5 = 40
So 40 is a multiple of 8
