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2 years ago

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Complete the following steps to find the LCD and write the sum of the numerators for the given problem: es002-1. Jpg Factor each

denominator: x2 – 3x – 4 = x2 – 6x 8 = The least common denominator is: (x − 4)(x )(x − ).

1 answer:

lesya [120]2 years ago

5 0

The value of x from the given equation is -4/3

<h3>Factorization</h3>

Given the quadratic equation x^2 – 3x – 4 = x^2 – 6x + 8

Collect the like terms

x^2 – 3x – 4 - x^2 + 6x - 8 = 0

-3x + 6x - 4 + 8 = 0

3x + 4 = 0

Subtrcat 4 from both sides

3x + 4 - 4 = 0 - 4

3x = -4

Divide both sodes by 3

3x/3 = -4/3

x = -4/3

Hence the value of x from the given equation is -4/3

Learn more on equations here: brainly.com/question/2972832

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Determine f(-1) if the graph of f(x) is given below.

-BARSIC- [3]

Answer:

$f(-1) = -2$

Step-by-step explanation:

Given

The attached graph

Required

$f(-1)$

This is the point where

$x = -1$

On the attached graph;

$f(x) = -2$ when $x = -1$

Hence:

$f(-1) = -2$

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3 years ago

You exercised 24 hours each month for a year. How many hours did you exercise by the end of the year? You may be able to do the

dedylja [7]

Answer:

288 hours.

Step-by-step explanation:

You exercise 24 hours in 1 month.

There are 12 months in one year.

24 * 12 = 288

Therefore, you exercised 288 hours in one year.

7 0

3 years ago

Read 2 more answers

Test scores of the student in a school are normally distributed mean 85 standard deviation 3 points. What's the probability that

Mrrafil [7]

Answer:

The probability that a random selected student score is greater than 76 is $\\ P(x>76) = 0.99865$ .

Step-by-step explanation:

The Normally distributed data are described by the normal distribution. This distribution is determined by two <em>parameters</em>, the <em>population mean</em> $\\ \mu$ and the <em>population standard deviation</em> $\\ \sigma$ .

To determine probabilities for the normal distribution, we can use <em>the standard normal distribution</em>, whose parameters' values are $\\ \mu = 0$ and $\\ \sigma = 1$ . However, we need to "transform" the raw score, in this case <em>x</em> = 76, to a z-score. To achieve this we use the next formula:

$\\ z = \frac{x - \mu}{\sigma}$ [1]

And for the latter, we have all the required information to obtain <em>z</em>. With this, we obtain a value that represent the distance from the population mean in standard deviations units.

<h3>The probability that a randomly selected student score is greater than 76</h3>

To obtain this probability, we can proceed as follows:

First: obtain the z-score for the raw score x = 76.

We know that:

$\\ \mu = 85$

$\\ \sigma = 3$

$\\ x = 76$

From equation [1], we have:

$\\ z = \frac{76 - 85}{3}$

Then

$\\ z = \frac{-9}{3}$

$\\ z = -3$

Second: Interpretation of the previous result.

In this case, the value is <em>three</em> (3) <em>standard deviations</em> <em>below</em> the population mean. In other words, the standard value for x = 76 is z = -3. So, we need to find P(x>76) or P(x>-3).

With this value of $\\ z = -3$ , we can obtain this probability consulting <em>the cumulative standard normal distribution, </em>available in any Statistics book or on the internet.

Third: Determination of the probability P(x>76) or P(x>-3).

Most of the time, the values for the <em>cumulative standard normal distribution</em> are for positive values of z. Fortunately, since the normal distributions are <em>symmetrical</em>, we can find the probability of a negative z having into account that (for this case):

$\\ P(z>-3) = 1 - P(z>3) = P(z$

Then

Consulting a <em>cumulative standard normal table</em>, we have that the cumulative probability for a value below than three (3) standard deviations is:

$\\ P(z$

Thus, "the probability that a random selected student score is greater than 76" for this case (that is, $\\ \mu = 85$ and $\\ \sigma = 3$ ) is $\\ P(x>76) = P(z>-3) = P(z$ .

As a conclusion, more than 99.865% of the values of this distribution are above (greater than) x = 76.

<em>We can see below a graph showing this probability.</em>

As a complement note, we can also say that:

$\\ P(z3)$

$\\ P(z3)$

Which is the case for the probability below z = -3 [P(z<-3)], a very low probability (and a very small area at the left of the distribution).

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3 years ago

H.E.L.P 100 POINTS!!! Match the addition and subtraction problems to their solutions: (See the picture)

Artist 52 [7]

Here you go,Please give Points.

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2 years ago

Lillian kicks a football. Its height in feet is given by h(t)= -16t^2+72th(t)=−16t 2 +72t where tt represents the time in second

Hitman42 [59]

The after 9/4 seconds the football is at its highest point which is 81 feet if Lillian kicks a football. Its height in feet is given by h(t)= -16t²+72t

<h3>What is a parabola?</h3>

It is defined as the graph of a quadratic function that has something bowl-shaped.

$\rm h(t)= -16t^2+72t$

Making perfect square:

$\rm h(t)= -[(4t)^2-72t+9^2 -9^2]$

$\rm h(t)= -[(4t-9)^2 -81]$

$\rm h(t)= 81-(4t-9)^2$

The highest point will be when term (4t-9)² becomes zero

So the highest point = 81 feet, and it takes:

t = 9/4 seconds

Thus, the after 9/4 seconds the football is at its highest point which is 81 feet if Lillian kicks a football. Its height in feet is given by h(t)= -16t²+72t

Learn more about the parabola here:

brainly.com/question/8708520

#SPJ1

7 0

2 years ago