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Charra [1.4K]
3 years ago
7

Jim Bob Airlines has one 57 seat plane. On its last five flights it had 44 passengers from MSY to DFW, 49 passengers from DFW to

OKL, 36 passengers from OKL to TUL, 30 passengers from TUL to FWB, and 49 passengers from FWB to MSY. For the last five flights, what was the load factor? (Make sure your answer is accurate to one decimal place)
Business
1 answer:
ahrayia [7]3 years ago
5 0

Solution:

Total number of seats in the plane = 57

From MSY to DFW = 44 passangers

From DFW to OKL = 49 passangers

From OKL to TUL = 36 passangers

From TUL to FWB = 30 passangers

From FWB to MYS = 49 passangers

So the average number of seats filled per flight

                                                                = (44+49+36+30+49) / 5

                                                                 = 208/5

                                                                  = 41.6

For the last 5 flights Load factor = Average number of seats filled per flight / Total number of seats in the plane

= 41.6 / 57

= 0.7298

= 72.9%

So for the last five flights the load factor was 72.9%

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Answer:

1 company to be in different is  15000 units

2 cost =  approximate  $300000

3 Total annual costs  = approximate $380,000

4  cost is less for phoenix and  Phoenix is the ideal location

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Explanation:

given data

Atlanta fixed costs (annual) = 80000

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solution

we consider here output level = x

and price will be = p

so here profit for location will be

profit = Revenue - Variable Cost - Fixed costs   .............1

so here Atlanta profit is  

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and Phoenix profit is  

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so now company to be in different is  

px - 20x - 80000 = px - 16.1x - 140,000

solve we get x here

x =  15,384.62  = 15000 units

and  

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annual cost =  Variable cost + Fixed     ...........4

cost = 16.1 × 10,000 + 140,000

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cost = $301,000 = approximate  $300000

and

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and

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so  

Cost for Atlanta  = 20 × 20000 + 80,000

Cost for Atlanta  = $480,000

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so cost is less for phoenix and  Phoenix is the ideal location

and

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