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Stells [14]
3 years ago
6

a 74 kg man jumps from a window 1.6 m above a sidewalk. the acceleration of gravity is 9.81 m/s 2 . a) what is his speed just be

fore his feet strike the pavement? answer in units of m/s
Physics
1 answer:
olasank [31]3 years ago
4 0

Answer:

  5.60 m/s

Explanation:

His initial potential energy is equal to his final kinetic energy.

  mgh = 1/2mv^2

  2gh = v^2 . . . . . . . multiply by 2/m

  v = √(2gh) = √(2(9.81 m/s²)(1.6 m)) = √(31.392 m²/s²)

  v ≈ 5.60 m/s

_____

<em>Additional comment</em>

The mass is irrelevant in the equations we typically use for this purpose.

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