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4 years ago

What strength can accurately be attributed to the force of the throw?

1 answer:

3 0

Well for example if you’re throwing a ball The force that moves the ball "up"
must overcome (be larger than) the downward force of the ball's weight.
Once the upward "force of the throw" overcomes the weight, it must then accelerate the ball upward, in order to give an initial upward speed.
Newton's formula: Fnet = ma
indicates that the acceleration (a) will equal the *excess upward force* {once the weight force is cancelled} divided by the ball's mass.
so in summary:
Fnet in Newtons will be the child's UPward force minus the ball's weight.

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A tired physics professor can easily read the fine print of the financial page when the newspaper is held at arm's length, 61.5

leva [86]

Answer:

45.04 cm

Explanation:

The tired physics professor red easily at a distance of 26 cm

So v = 26 cm

And it is given that object distance that is u = 61.5 cm

There is relation between focal length object distance and image distance that is $\frac{1}{f}=\frac{1}{v}-\frac{1}{u}$

Here f =focal distance v = image distance and u = object distance

So $\frac{1}{f}=\frac{1}{26}-\frac{1}{61.5}$

So f=45.04 cm

3 0

3 years ago

How many grams of ammonium chloride is soluble at 50 C

user100 [1]

Ammonium chloride is soluble at 80g.

5 0

3 years ago

a block with a mass of 3 kg is swung on a cord in a horizontal circle with a radius of 2m. the speed of the block is 6m/s^. the

Ivenika [448]

Given Information:

Mass = m = 3 kg

Speed = v = 6 m/s

Radius = r = 2 m

Required Information:

Magnitude of the acceleration = a = ?

Answer:

Magnitude of the acceleration = 18 m/s²

Explanation:

The acceleration of the block traveling along a circular path with some velocity is given by

a = v²/r

a = 6²/2

a = 36/2

a = 18 m/s²

Therefore, the magnitude of the acceleration of the block is most nearly equal to 18 m/s².

Bonus:

The corresponding force acting on the block can be found using

F = ma (a = v²/r)

F = mv²/r

7 0

3 years ago

Read 2 more answers

2. A 2,000 kg rocket is launched 12 km straight up at a constant acceleration into the sky at which point the rocket is travelli

Mice21 [21]

Answer:

797700000 J

Explanation:

From the question,

The work done by the rocket, is given as,

W = Ek+Ep............. Equation 1

Where Ek and Ep are the potential and the kinetic energy of the rocket respectively.

Ep = mgh............ Equation 2

Ek = 1/2mv²............. equation 3

Substitute equation 2 and equation 3 into equation 1

W = mgh+1/2mv².............. Equation 4

Where m = mass of the rocket, h = height, v = velocity of the rocket, g = acceleration due to gravity.

Given: m = 2000 kg, h = 12 km = 12000 m, v = 750 m/s, g = 9.8 m/s²

Substitute into equation 4

W = 2000(12000)(9.8)+1/2(2000)(750²)

W = 235200000+562500000

W = 797700000 J

6 0

3 years ago

A heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h. I

Natali5045456 [20]

The power that heat pump draws when running will be 6.55 kj/kg

A heat pump is a device that uses the refrigeration cycle to transfer thermal energy from the outside to heat a building (or a portion of a structure).

Given a heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h and if the COP of the heat pump is 2.8

We have to determine the power the heat pump draws when running.

To solve this question we have to assume that the heat pump is at steady state

Let,

Q₁ = 22000 kj/kg

COP = 2.8

Since heat pump used to heat a house runs about one-third of the time.

So,

Q₁ = 3(22000) = 66000 kj/kg

We known the formula for cop of heat pump which is as follow:

COP = Q₁/ω

2.8 = 66000 / ω

ω = 66000 / 2.8

ω = 6.66 kj/kg

Hence the power that heat pump draws when running will be 6.55 kj/kg

Learn more about heat pump here :

brainly.com/question/1042914

#SPJ4

5 0

2 years ago