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3 years ago

A gold bar has a density of 19.3 g/mL. If the gold bar has a mass of 6.3 grams, what is the volume?

Physics

1 answer:

Natali [406]3 years ago

7 0

Answer:

The correct answer is "0.32 mL".

Explanation:

The given values are:

Density of gold bar,

d = 19.3 g/mL

Mass of gold bar,

m = 6.3 grams

Now,

The volume will be:

⇒ $Density = \frac{Mass}{Volume}$

or,

⇒ $Volume=\frac{Mass}{Density}$

On substituting the values, we get

⇒ $=\frac{6.3 \ g}{19.3 \ g/mL}$

⇒ $=0.32 \ mL$

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Consider a system made of a ramp that has a run of 8 m and a rise of 6 m. Two equal masses of 4-kg are connected to each other b

djyliett [7]

Answer:

The force of friction is 15.68 N.

Explanation:

Given:

Rise is 6 m and run is 8 m.

Mass of each body (m) = 4 kg

The whole system is in equilibrium.

Now, consider the diagram below representing the scenario given in the question.

The forces acting on the mass that is hanging are tension force in the upward direction and weight of the body acting vertically downward.

As the mass is in equilibrium, the total upward force equals total downward force. So,

$T= mg=4\times 9.8=39.2\ N$ -------- (1)

Now, the forces acting on the other mass along the ramp are:

1. Tension (T) up the ramp

2. $mg sin\theta$ and frictional force (f) down the ramp

Now, as per question:

Rise = 6 m and run = 8 m

So, from figure,

$\tan\theta=\frac{6}{8}=0.75\\\\\theta=\tan^{-1}(0.75)=37\°$

Now, $\sin\theta=\sin(37\°)=0.6$

Now, as the other mass is also at rest, net force acting on it is also 0. So,

$F_{net}=0\\\\T-(mg\sin\theta+f)=0\\\\mg\sin\theta+f=T\\\\f=T-mg\sin\theta$

Now, plug in the given values and solve for 'f'. This gives,

$f=39.2-(4\times 9.8\times 0.6)\\\\f=39.2-23.52=15.68\ N$

Therefore, the force of friction is 15.68 N

4 0

4 years ago

The solar constant is a. the same for a sphere or for a circle. b. only about a quarter of all energy emitted by the sun. c. a c

kvasek [131]

Answer:

Explanation:

5 0

3 years ago

Alex swims at an average speed of 4.5 m/s how far does he swim in one minute 24 seconds

Zepler [3.9K]

Answer:

378

Explanation:

60 seconds in one minute

add the 24 seconds

multiply it by 4.5

60 + 24 = 84

4.5 x 84 = 378

8 0

3 years ago

Soccer fields vary in size. a large soccer field is 115 m long and 85 m wide. what are its dimensions in feet and inches? (assum

Irina18 [472]

The dimension of soccer field in ft is 377.315 ft long and 277.885 ft in width.

The dimension of soccer field in ft is 4527.78 in long and 3334.62 in in width.

As it is given that 1 m =3.281 ft

Therefore the length of the soccer field in ft is

115*3.281=377.315 ft

And width of the field is 85*3.281=277.885 ft

We know that 1 ft =12 in

Therefore the length of the soccer field in in is

377.315*12=4527.78 in

And width of the field is 277.885 *12=3334.62 in

8 0

3 years ago

What current flows when a 35 v potential difference is imposed across a 1.4 kω resistor?

svetlana [45]

Current = (voltage) / (resistance)

= (35 volts) / (1,400 ohms)

= 25 milliamperes

5 0

3 years ago