Answer:
4 m/s² down
Explanation:
We'll begin by calculating the net force acting on the object.
The net force acting on the object from the left and right side is zero because the same force is applied on both sides.
Next, we shall determine the net force acting on the object from the up and down side. This can be obtained as follow:
Force up (Fᵤ) = 15 N
Force down (Fₔ) = 25 N
Net force (Fₙ) =?
Fₙ = Fₔ – Fᵤ
Fₙ = 25 – 15
Fₙ = 10 N down
Finally, we shall determine the acceleration of the object. This can be obtained as follow:
Mass (ml= 2.5 Kg
Net force (Fₙ) = 10 N down
Acceleration (a) =?
Fₙ = ma
10 = 2.5 × a
Divide both side by 2.5
a = 10 / 2.5
a = 4 m/s² down
Therefore, the acceleration of the object is 4 m/s² down
It slows the object down so it cannot move well and evetually the object cannot be pushed and farther
The distance is 17 and the displacement is 1
Answer:
24 cm/s
Explanation:
Applying
Pythagoras theorem,
a² = b²+c²............. Equation 1
Where a = resultant, b = vertical component, c = horizontal component
From the question,
Given: a = 26 cm/s, c = 10 cm/s
Substitute these values into equation 1
26² = b²+10²
676 = b²+100
b² = 676-100
b² = 576
b = √576
b = 24 cm/s
Answer:
The velocity is 
Explanation:
From the question we are told that
The frequency of the signal sent out is 
The frequency of the signal received is 
The speed of sound is 
Generally the frequency of the sound received is mathematically represented as
![f_r = f_s [\frac{v_s + v}{v_s - v} ]](https://tex.z-dn.net/?f=f_r%20%3D%20%20f_s%20%20%5B%5Cfrac%7Bv_s%20%20%2B%20v%7D%7Bv_s%20%20-%20v%7D%20%5D)
where v is the velocity of the object
=> ![40 *10^{3} = 38 *10^{3} * [\frac{341 + v}{341 - v} ]](https://tex.z-dn.net/?f=40%20%2A10%5E%7B3%7D%20%3D%20%2038%20%2A10%5E%7B3%7D%20%2A%20%20%20%5B%5Cfrac%7B341%20%20%2B%20v%7D%7B341%20%20-%20v%7D%20%5D)
=> 
=> 
=> 
=>
