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Andreyy89
3 years ago
5

How much kinetic energy does a moving 100 kg object have if it is moving at 5 m/s?

Physics
1 answer:
Vesnalui [34]3 years ago
4 0

Answer:

The object has 1250 Joules of Kinetic Energy.

Explanation:

Kinetic Energy = \frac{1}{2}mass*velocity²

KE = \frac{1}{2}mv²

KE = \frac{1}{2}(100kg)(5m/s)²

KE = \frac{1}{2}(100kg)(25m/s²)

KE = 1250\frac{kg}{m/s^2}

KE = 1250J

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3 years ago
A 125kg bumper car going 12m/s hits a 235kg bumper car going -13m/s.if the first car bounces back at -12.5m/s what is the veloci
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According to the law of conservation of momentum:

m_{1}v_{1}+m_{2}v_{2}=m_{1}v_{1}'+m_{2}v_{2}'

m1 = mass of first object
m2 = mass of second object
v1 = Velocity of the first object before the collision
v2 = Velocity of the second object before the collision
v'1 = Velocity of the first object after the collision
v'2 = Velocity of the second object after the collision

Now how do you solve for the velocity of the second car after the collision? First thing you do is get your given and fill in what you know in the equation and solve for what you do not know. 

m1 = 125 kg     v1 = 12m/s      v'1 = -12.5m/s
m2 = 235kg      v2 = -13m/s     v'2 = ?

m_{1}v_{1}+m_{2}v_{2}=m_{1}v_{1}'+m_{2}v_{2}'
(125kg)(12m/s)+(235kg)(-13m/s)=(125kg)(-12.5m/s)+(235kg)(v_{2}'
1,500kg.m/s+(-3055kg.m/s)=(-1562.5kg.m/s)+(235kg)(v_{2}')
-1,555kg.m/s=(-1562.5kg.m/s)+(235kg)(v_{2}')

Transpose everything on the side of the unknown to isolate the unknown. Do not forget to do the opposite operation. 

-1,555kg.m/s + 1562.5kg.m/s=(235kg)(v_{2}')
7.5kg.m/s=(235kg)(v_{2}')
(7.5kg.m/s)/(235kg)=(v_{2}')
0.03m/s=(v_{2}')

The velocity of the 2nd car after the collision is 0.03m/s.
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3 years ago
A person is attracted towards the center of the earth by an 800 N gravitational force. The force with which the earth is attract
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Answer:

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