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Bezzdna [24]
3 years ago
5

26 24 The length of the unknown leg is

Mathematics
1 answer:
Mamont248 [21]3 years ago
3 0
The length of the unknown leg is 2. Hope this helps:)
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Find the value of 5w+1 given that 7w-7=7.
Katyanochek1 [597]

Answer:

lets find the exact value of w

7w - 7 = 7

+7        +7

7w = 14

/7     /7

w = 2

Now let's replace w with 2

5(2) + 1 = 11

4 0
2 years ago
2 is 4% of what number?
kaheart [24]
x-searched\ number\\\\4\%x=2\\\\0.04x=2\ \ \ \ |:0.04\\\\x=50\\\\2\ is\ 4\%\ of\ 50
6 0
3 years ago
Help me with this please I will give you brainlist!
Volgvan

Answer:

it might be D

Step-by-step explanation:

im pretty sure

4 0
3 years ago
Heeeeeeeeeeeeeeeeeeeelllllppp​
adoni [48]

Answer:

120 degrees.

Step-by-step explanation:

All the angles in a triangle add up to 180. You have two of the angles given:

50 degrees and 70 degrees

To find the third angle of the triangle (BAC), use the expression:

180 - (50 + 70)

180 - 120

60

So, the third angle in the triangle is 60 degrees. Looking at angle DAB, you can see that it forms a straight line with angle BAC. A straight line is 180 degrees. Since we know BAC is 60, and BAC + DAB = 180, by doing 180 - 60, you can see that angle DAB is 120 degrees.

7 0
2 years ago
how many gallons of a 50 antifreeze solution must be mixed with 90 gallons of 20% antifreeze to get a mixture that is 40% antifr
Tamiku [17]
Try this:
1) note that weight of pure antifreeze before mixing and after mixing is the same. So, if 'x' is weight of pure antifreeze in 50% solution, it is possible to make up equation before mixing: 0.5x+0.2*90.
2) there are 0.2*90=18 gal. of pure antifreeze in the 20% solution. If 'x' gal. is the weight of pure antifreeze in 50% sol. and 18 gal. is the weight of pure antifreeze in 20% sol., it is possible to make up an equation after mixing: 0.4(x+18).
3) using the both parts: 0.5x+0.2*90=0.4(x+18) ⇒ x=54 gal. of <u>pure</u> weight.
4) to find 50% solution of 54 gal. pure weight just 54:0.5=108 gal.
Answer: 108 gal.
3 0
3 years ago
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