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1 year ago

Which of these relations are functions? Select all that apply.

Mathematics

1 answer:

Lemur [1.5K]1 year ago

8 0

Answer:

the first one on the top and the second one on the bottom

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Solve 5x - 3y = 9 for y.

LenKa [72]

5x - 3y = 9
5x = 9 + 3y
5x - 9 = 3y
( 5x - 9 ) / 3 = y
y = ( 5 / 3x ) - ( 9 / 3 ) ( I just split the common denominator to individual parts )
y = 5 / 3x - 3

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2 years ago

Please help!! fast!! -Geometry- ** will make you brainliest **

Hunter-Best [27]

abcd is a parallelogram

Step-by-step explanation:

so yiu gotta like 1 angle to the 2 angle buy thats seprare from the 3 angle to the 4 angle

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2 years ago

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Area of ice rink is 404 sq yes what is perimeter

ololo11 [35]

Ok, since the ice rink is a square (which has equal sides) if you multiply 404 times four because a square has 4 sides which is equal to 1616 the perimiter is 1616 sqf

404*4= 1616 p= 1616sq

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2 years ago

The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further from the lighthouse. The new bearing is 25°

djverab [1.8K]

Answer:

The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.

Step-by-step explanation:

The question is incomplete. The complete question should be

The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?

Given the initial bearing of a lighthouse from the ship is N 37° E. So, $\angle ABN$ is 37°. We can see from the diagram that $\angle ABC$ would be $180-37=$ 143°.

Also, the new bearing is N 25°E. So, $\angle BCA$ would be 25°.

Now we can find $\angle BAC$ . As the sum of the internal angle of a triangle is 180°.

$\angle ABC+\angle BCA+\angle BAC=180\\143+25+\angle BAC=180\\\angle BAC=180-143-25\\\angle BAC=12$

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.

And let us assume the distance between the lighthouse and the ship at N 25°E is $AC=x$

We can apply the sine rule now.

$\frac{x}{sin(143)}=\frac{2.5}{sin(12)}\\ \\x=\frac{2.5}{sin(12)}\times sin(143)\\\\x=\frac{2.5}{0.207}\times 0.601\\ \\x=7.26\ miles$

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.

3 0

2 years ago

16 increased by twice a munber is -24

dangina [55]

We can form this algebraic equation to work the equation out:

16 + 2x = -24
2x = -40
x - 20

Hope I helped.

8 0

2 years ago