A)
To be similar triangles have to have equal angles
triangle ZDB'
1)angle Z=90 degrees
triangle B'CQ
1) angle C 90 degrees
angle A'B'Q=90
DB'Z+A'B'Q+CB'Q=180, straight angle
DB'Z+90+CB'Q=180
DB'Z+CB'Q=90
triangle ZDB'
DZB'+DB'Z=180-90=90
DB'Z+CB'Q=90
DZB'+DB'Z=90
DB'Z+CB'Q=DZB'+DB'Z
2)CB'Q=DZB' (these angles from two triangles ZDB' and B'CQ )
3)so,angles DB'Z and B'QC are going to be equal because of sum of three angles in triangles =180 degrees and 2 angles already equal.
so this triangles are similar by tree angles
b)
B'C:B'D=3:4
B'D:DZ=3:2
CQ-?
DC=AB=21
DC=B'C+B'D (3+4= 7 parts)
21/7=3
B'C=3*3=9
B'D=3*4=12
B'D:DZ=3:2
12:DZ=3:2
DZ=12*2/3=8
B'D:DZ=CQ:B'C
3:2=CQ:9
CQ=3*9/2=27/2
c)
BC=BQ+QC=B'Q+QC
BQ' can be found by pythagorean theorem
Answer:
The System of inequality is ,
1. y > 2 x + p
2. y < 2 x + p
Suppose we assign some values to p and q and draw its graph
And, then the inequality sign on both inequalities is reversed
3. y < 2 x + p
4. y > 2 x + p
And , then draw it's graph
it has been found that, the solution set of both the inequality remains same.That is there is no point or set of points , which satisfy both the system of inequality.
The system has no solution.
Answer:
B it right...
Step-by-step explanation:
One can prove congruence through transformation if they have the same shape and size.
The congruency postulates include:
- SSS - Side-Side-Side
- SAS - Side-Angle-Side
- ASA- Angle-Side-Angle
- AAS - Angle-Angle-Side
- RHS - Right angle-Hypotenuse-Side
<h3>What is congruence?</h3>
In geometry, it should be noted that two figures are congruent if they have the same shape and size.
In this case, if two angles and a non-included side of one triangle are equal to two angles and a non-included side of another triangle, then the triangles are congruent.
One can prove triangle congruence using congruency postulates by using the SSS theorem( side side side theorem).
It should be noted that the congruence postulate is used to illustrate that the triangles are equal.
Learn more about congruence on:
brainly.com/question/2938476
#SPJ1
Answer: 0.0668073
Step-by-step explanation:
Given : The number of miles each tire lasts before it completely wares out follows a normal distribution with mean μ = 50,000 miles and standard deviation σ = 8,000 miles.
Let x be the random variable that represents the number of miles each tire lasts.
z-score : 
For x= 62,000
By using the standard z-value table , the probability for a randomly selected tire to last for at least 62,000 miles will be :_
Hence, the probability for a randomly selected tire to last for at least 62,000 miles = 0.0668073
