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alekssr [168]
3 years ago
8

Solve for X 4x-5=2x+3

Mathematics
2 answers:
Tom [10]3 years ago
7 0

Answer:

x = 4

Step-by-step explanation:

4x-5=2x+3

subtract 2x from both sides

2x-5=3

add 5 to both sides

2x=8

divide both sides by 2

x=4

Phantasy [73]3 years ago
6 0
I’ve provided both the answer and explanation below! Hope this helps :)

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I need help with this question... the topic is solving linear systems of equations using elimination (addition). Please give exp
gregori [183]

Answer:

x= -1

y=2

Step-by-step explanation:

6x+5y=4

6x-7y=-20

Subtract

7 0
2 years ago
Solve for t. 5(t + 3)= -3.5
sattari [20]

Answer:

Step-by-step explanation:

5(t+3)=-3.5

distribute

5t+15=-3.5

subtract 15 from both sides

5t= -18.5

divide both sides by 5

t=-3.7

5 0
2 years ago
The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

5 0
3 years ago
X y
zhannawk [14.2K]

Answer:

uhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Step-by-step explanation:

8 0
3 years ago
Plz, I need the answer ASAP!
densk [106]
The answer is in my attachment

7 0
3 years ago
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